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julsineya [31]
3 years ago
8

For problem 2,f(2) =

Mathematics
1 answer:
just olya [345]3 years ago
6 0

Answer:

4f

Step-by-step explanation:

Simplify & Multiply :)

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Factor. 8a2−2ac+12ab−3bc
Masteriza [31]

Answer:

B. (2a +3b)(4a -c)

Step-by-step explanation:

Group the terms pairwise, then factor each pair.

... (8a² -2ac) +(12ab -3bc)

2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.

... = 2a(4a -c) +3b(4a -c)

Then we see that (4a-c) is a common factor in the result. We can factor that out.

... = (2a +3b)(4a -c) . . . . matches selection B

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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question one

1, 2, 3, 4, 5, 6

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you use the list from question one, and count how many fit the criteria and put that number over the total ( which is 6 in this case )

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