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iren [92.7K]
3 years ago
7

In how many ways can the letters in the word "math" be arranged?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
Number of ways = 4! = 4 x 3 x 2 x 1 = 24

Answer: 24
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Can you answer these? I don't understand this part either. Thanks
Flura [38]
9x+10=12x-11
We put 12x on the left side and 10 on right side
9x-12x=-11-10
Now we add x and free numbers 
-3x=-21
And our result is:
x=7

3(x-8)=5x+7
3x-24=5x+7
3x-5x=7+24
-2x=31
x=- \frac{31}{2}
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gayaneshka [121]

Answer:

does anyone have a what

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3 years ago
Work out <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\frac{1}{5}" align="
NNADVOKAT [17]

Answer:

Here we will explain how to calculate one half of 80.

One half of 80 is simply one half times 80, which can be written as follows:

One/half x 80

Furthermore, you can convert "one" to "1" and "half" to "2" and then the equation and answer is:

1/2 x 80 = 40.00

Step-by-step explanation:

7 0
2 years ago
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If a watch has a 0.12 defect rate. what is the probability that the watch has fewer than 3 defects in a run of 75 chimes?
Maslowich

Answer:

(\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Step-by-step explanation:

If a watch has fewer than three defects, then either 1.) It has no defects, 2.) it has exactly 1 defect, or 3.) it has exactly 2 defects.

1.) The probability that the watch has no defects is (\frac{88}{100})^{75}, because for every chime there is a probability of \frac{88}{100} that there is no defect

2.) The probability that the watch has exactly 1 defect is (\frac{88}{100})^{74}(\frac{12}{100}) times the number of ways you can choose 1 of 75 of the chimes to be defective, which is \binom{75}{1}, so the probability that the watch has exactly 1 defect is \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}).

3.) For the same reason as 2.), the probability that the watch has exactly two defects is \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Since 1.), 2.), and 3.) are mutually exclusive events, the probability of their union is simply the probability of each of them added together, which is (\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

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3 years ago
Of the 250 sheep in a flock,<br> 34% are spotted what is the total of spotted sheep
denis-greek [22]
The answer is 85 sheep are spotted

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4 years ago
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