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luda_lava [24]
3 years ago
11

1 2.5n + 3.5p = 825.5

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

read explanation

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

n = 330.2 − 1.4p

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Given the system of equations:
kolezko [41]
2x=16-2y
x=8-y

6(8-y)+4y=38
48-6y+4y=38
48-2y=38
-2y=-10
y=5

8-5=x
x=3 <-Answer
4 0
3 years ago
Write the equation of the line through (3,9) and (-2,9)
strojnjashka [21]

Answer:

y = 9

Step-by-step explanation:

y-y1 = m(x-x1)

m is the slope =y2-y1/x2-x1=9-9/-2-3=0

pick any number out of the given two for (x1, x2)

y-9 = 0*(x-3) so

y-9 = 0 add 9 to both sides

y = 9

5 0
2 years ago
A triangle is rotated 90° about the origin. Which rule describes the transformation?
Over [174]

Answer:

B

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
Priya ran 1 ½ miles today, and Tyler ran 3 ¾ miles today. How many times the length of Tyler's run was Priya's run?
krek1111 [17]
Answer:
2.5
Step-by-step explanation:
6 0
3 years ago
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