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shtirl [24]
3 years ago
10

a sports team donates 157 tickets to a sporting event,with tickets to be shared equally among 9 classrooms.How many tickets does

each classroom receive? How many tickets are left over?
Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

Each class should get 17 tickets. 4 tickets will be left over.

Step-by-step explanation:

157/9=17.444... -> 17 per class

17 x 9 = 153

157-153= 4 left

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7 0
3 years ago
Let (3, -2) be a point on the Terminal Side of θ. Find the exact values of Cosθ, Secθ, and Cotθ
V125BC [204]

\bf (\stackrel{a}{3}~,~\stackrel{b}{-2})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c = \sqrt{3^2+(-2)^2}\implies c=\sqrt{9+4}\implies c=\sqrt{13} \\\\[-0.35em] ~\dotfill

\bf cos(\theta )\implies \cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{\sqrt{13}}}\implies \cfrac{3}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies \cfrac{3\sqrt{13}}{13} \\\\\\ sin(\theta )\implies \cfrac{\stackrel{opposite}{-2}}{\stackrel{hypotenuse}{\sqrt{13}}}\implies \cfrac{-2}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies \cfrac{-2\sqrt{13}}{13} \\\\\\ cot(\theta )\implies \cfrac{\stackrel{adjacent}{3}}{\stackrel{opposite}{-2}}

8 0
3 years ago
Please help and solve for each will give brainliest
sergiy2304 [10]
Comment
The measurement of an arc in degrees is the same as the central angle. We must assume that the central angle is the measurement given. 
\overset{\LARGE{\frown}}{AB} = 49

To find the next one you need to find the measurement from B to C, the arc that is over 180 degrees. Maybe you could put another letter between B and C so that we could refer to that top arc greater than 180 degrees. Call the point you inserted  D. 

\overset{\LARGE{\frown}}{BDC} = 360 - 49 - 107 = 204
\overset{\LARGE{\frown}}{ABC} = \overset{\LARGE{\frown}}{BDC} + \overset{\LARGE{\frown}}{AB} 

Arc(ABC) = 204 + 49 = 253

Arc(BAC) = Arc(BC) + Arc(AB)
Arc(BAC) = 107 + 49
Arc(BAC) = 156

Arc(ACB) = 107 + 204 = 311   


 

5 0
3 years ago
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