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prohojiy [21]
3 years ago
6

For what value of 0, in degrees, is sin 0 = cos 58°​

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

sin32°

Step-by-step explanation:

Using the cofunction identity

cosx = sin(90 - x) , then

cos58° = sin(90 - 58)° = sin32°

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The student will be able to fill  5 1/2 cups of lemonade.

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Write an equation in slope-intercept form for the line that has the given slope and contains the point. Please show some work.(
Paha777 [63]

Answer:

An equation in the slope-intercept form will be:

y=-\frac{1}{2}x+0

Step-by-step explanation:

Given the points

  • (4, -2)
  • (2, -1)

Finding the slope between the points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(4,\:-2\right),\:\left(x_2,\:y_2\right)=\left(2,\:-1\right)

m=-\frac{1}{2}

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

substituting the values m=-1/2 and the point (4, -2) to determine the y-intercept i.e. 'b'.

y=mx+b

-2=-\frac{1}{2}\left(4\right)+b

\frac{1}{2}\cdot \:4+b=-2

-2+b=-2

b=0

Now, substituting the values b=0 and m=-1/2 to determine the equation in the slope-intercept form.

y=mx+b

y=-\frac{1}{2}x+0

Thus, an equation in the slope-intercept form will be:

y=-\frac{1}{2}x+0

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Answer:

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6y - 9x = 12; add 9x on both sides

6y = 9x + 12; divide 6 on both sides

y = 9/6x + 12/6

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next to make a line *perpendicular* to this, we make the slope negative and swap the fraction (-2/3)

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