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2 years ago

Find the slope of the line that passes through (6, 3) and (10, 6)

Mathematics

1 answer:

Oxana [17]2 years ago

3 0

Step-by-step explanation:

3/4

insert 1st point into y=mx+b

3=m(6)+b

insert 2nd point into y=mx+b

6=m(10)+b

-----------------------------------

use system of equations to solve for m and b

b=3-6m

b=6-10m

3-6m=6-10m

4m=3

m=3/4

insert back into the equation

3=(3/4)6+b

3=9/2+b

3-9/2=b

-3/2=b

insert back into y=mx+b

m=slope

b=y-intercept

y=(3/4)x-3/2

slope=3/4

Hope that helps :)

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3 years ago

Kent and Bradley both work at a car dealership. Kent makes $10/hour + 3% on the amount of sales he completes. Bradley only makes

Masteriza [31]

Answer: There is difference of $660 in their paychecks.

Step-by-step explanation:

Since we have given that

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Similarly, Bradley only makes $7 per hour but he makes 4% on the amount of his sales .

So, the equation for Bradley becomes,

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2 years ago

I NEED HELP PLEASE, THANKS! :)

Elena L [17]

Answer:

First option is the right choice.

Step-by-step explanation:

$\frac{1}{\cos \left(x\right)+1}+\frac{1}{\cos \left(x\right)-1}\\\\\frac{\cos \left(x\right)-1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}+\frac{\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{\cos \left(x\right)-1+\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{2cos\left(x\right)}{cos^2\left(x\right)-1}\\\\=\frac{2cos\left(x\right)}{sin^2\left(x\right)}$

$=2\cdot \frac{cos\left(x\right)}{sin\left(x\right)}\cdot \frac{1}{sin\left(x\right)}\\\\=-2cot(x)csc(x)$

Best Regards!

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