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vaieri [72.5K]
3 years ago
8

Roxie is picking out some movies to rent, and she is primarily interested in horror films and foreign films. She has narrowed do

wn her selections to 20 horror films and 8 foreign films. Step 2 of 2 : How many different combinations of 3 movies can she rent if she wants at least two horror films
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

2470

Step-by-step explanation:

Roxie must pick 3 movies from 20 horror films and 8 foreign films with at least two horror films.

i) She can pick 2 horror films and 1 foreign film

The number ways this is possible = C(20, 2) * C(8, 1)

C(20,2)=\frac{20!}{(20-2)!2!}=190\\\\C(7,1)=\frac{7!}{(7-1)!1!}=7

The number ways this is possible = C(20, 2) * C(8, 1) = 190 * 7 = 1330

ii) She can pick 3 horror films

The number ways this is possible = C(20, 3)

C(20,3)=\frac{20!}{(20-3)!3!}=1140\\\\

The number ways this is possible = C(20, 3) = 1140

The number of ways of picking 3 movies from 20 horror films and 8 foreign films with at least two horror films = pick 2 horror films and 1 foreign film + pick 3 horror films

The number of ways of picking 3 movies from 20 horror films and 8 foreign films with at least two horror films = 1330 + 1140 =2470

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Step-by-step explanation:

We need to find the common difference and the recursive formula.

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First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

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