Calculate

True or false? Postulates are statements that are accepted without question or justification

ale4655 [162]

<span>True, as a postulate is the assumption of existence.</span>

6 0

3 years ago

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When calculating correlation and regression both sets of data must be __________

Misha Larkins [42]

When calculating correlation and regression both sets of data must be Statistical.

According to the statement

we have to find the type of data when we calculate the correlation and regression both sets.

so, The difference between these two statistical measurements is that correlation measures the degree of a relationship between two variables (x and y), whereas regression is how one variable affects another.

And when we calculate both then data sets must be a statistical data. because correlation summarizing direct relationship between two variables and regression predict or explain numeric response. So, without statistical data this is not possible to calculate correlation and regression both sets.

so, When calculating correlation and regression both sets of data must be Statistical.

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7 0

1 year ago

1. Writing an equation for an exponential function by

Naya [18.7K]

Answer: 1) $t(n)=0.6(2)^n$

2) $f(x)=10(5)^x$

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

$t(n) = ab^n$ ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

$0.6 = a(b)^0\implies 0.6 = a$

Hence the function that shows the given situation,

$t(n) = 0.6 b^n$ -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

$1.2 = 0.6 b^1\implies 2 = b$

Thus, the complete function is,

$t(n) = 0.6 (2)^n$

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = ab^x$ ---------(1)

For f(x) = 2, x = -1

By equation (1),

$2= ab^{-1}$ ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

$\frac{2}{5}= a(b)^{-2}$

$\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}$

$\implies \frac{2}{5}=\frac{2}{b}$

$\implies 2b=10$

$\implies b = 5$

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = 10(5)^x$

5 0

3 years ago

Write a few sentences about different was to show subtraction for a problem like 32-15

iogann1982 [59]

I had 32 cookies and I wanted to give 14 of my friends a cookie each, how many cookies are left?

I went to the pet store with $32 and i bought a $15 for my dog, how much money do I have left?

My friend (insert any random name here) was biking a 32 mile race, he/she has gone 15 miles so far, how many more miles does (their name here) have to bike?

8 0

3 years ago

I need answer by 2:25!!!! Please hurry!!!!!

Alinara [238K]

Answer:

C

Step-by-step explanation:

-2^4-5(5)+2(-2-3)^2

16-25+2(25)

16-25+50

41

7 0

3 years ago

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