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3 years ago

Utilizing the following graph, give the quadrant of point A.

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

Answer:

Quadrant 2

Step-by-step explanation:

The top right corner is Quadrant 1, the top left corner is Quadrant 2, the bottom left corner is Quadrant 3, and the bottom right corner is Quadrant 4.

The point A is in the top left corner, meaning that it's in Quadrant 2.

Hope this helps!

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g Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = 7yi + xzj + (

Sati [7]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is any oriented surface with boundary $C$ . We have

$\vec F(x,y,z)=7y\,\vec\imath+xz\,\vec\jmath+(x+y)\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-7)\,\vec k$

Take $S$ to be the ellipse that lies in the plane $z=y+9$ with boundary on the cylinder $x^2+y^2=1$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(u\sin v+9)\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath+u\,\vec k$

Then we have

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^1\big((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+2)\,\vec k\big)\cdot\big(-u\,\vec\jmath+u\,\vec k\big)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^1(3u+u^2\sin v)\,\mathrm du\,\mathrm dv=\boxed{3\pi}$

5 0

3 years ago

Which of the following is a factor of 30x2 + 37x + 10?

VashaNatasha [74]

your answers is A)5x + 2

5 0

3 years ago

How do the values of the 5s in 581.03 and 5.472 compare

Nonamiya [84]

The value of the 5 in 581.03 is 100 times the value of the 5 in 5.472

Step-by-step explanation:

Each digit in a number has a place value.

The place value of 4 in 453.56 is hundreds (100), because 4 is in the hundred place

The place value of 2 in 1782.56 is ones (1), because 2 is in the unit place

The place value of 3 in 2.345 is tenth (0.1), because 3 is in the tenth place

∵ The number is 581.03

- Find the place of 5 in the number

∵ 5 is in the hundred place

∴ The place value of 5 is 100

∵ The number is 5.472

- Find the place of 5 in the number

∵ 5 is in the unit place

∴ The place value of 5 is 1

To find the value of the 5 in 581.03 is how many times the value of the 5 in 5.472 divide the place values of them

∵ 100 ÷ 1 = 100

∴ The value of 5 in 581.03 = 100 times the value of 5 in 5.472

The value of the 5 in 581.03 is 100 times the value of the 5 in 5.472

6 0

3 years ago

Find the area of the parallelogram

BartSMP [9]

6*14=84
the answer is 84cm²

7 0

4 years ago

Read 2 more answers

At the city museum, child admission is $5.20 and adult admission is $9.90 . On Monday, twice as many adult tickets as child tick

DiKsa [7]

To solve this, I would just find what two adult tickets and one child ticket wold be worth.

To find that, just do:

5.20 + 9.90 * 2, which makes 25.

So now you just find how many 25s are in 900, or 36.

So 36 children's tickets were sold that day.

Hope I helped :)

7 0

3 years ago