The standard deviation of the sample mean differences is 4.854
<h3>How to determine the standard deviation of the sample mean differences?</h3>
The table of values is given as:
<u>Sample Standard deviation</u>
Red box 3.868
Blue box 2.933
The standard deviation of the sample mean differences is calculated using:
This gives
Evaluate the expression
Also, the table of value do not give any information regarding the sample size.
This means that the sample size of the session regarding the number of people would purchase the red box and the blue box are unknown
Hence, the standard deviation of the sample mean differences is 4.854
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Answer:
b = 14
Step-by-step explanation:
Since both angles are diagonal each other, they are equal to each other.
5b = b + 56
-b -b (subtract b from both sides)
<u>4b</u> = <u>56</u>
4 4 (divide both sides by 4 to solve for b)
b = 14
6. One variable only so pretty straightforward.
length-x+4
width-x
x+x+4=80
2x=76
x=38
x+4=42
answer: length 42cm and width 38cm
7. Another money problem!
n-# of nickels
q-# of quarters
n=3+q
0.05n+0.25q=2.85
Substitution works like a charm!
0.05(3+q)+0.25q=2.85
0.15+0.05q+0.25q=2.85
0.3q=2.7
q=9
n=3+q
n=3+9
n=12
answer: 9 nickels and 12 quarters
8. One variable situation again.
Ann's money-2b+9
Betty's money-b
b+2b+9=60
3b=51
b=17
2b+9=43
answer: Ann has $43 and Betty has $17.
9. # of red m&m's-x+1
# of blue m&m's-x
x+1+x=13
x=6
x+1=7
answer: 6 blue and 7 red m&m's
10. a-number of adult tickets
s-number of student tickets
a+s=785 ----> a=785-s
5a+2s=3280
5(785-s)+2s=3280
-3s=-645
s=215
a+s=785
a+215=785
a=570
answer: 215 children tickets and 570 adult tickets
