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Artist 52 [7]
2 years ago
8

What's 9/5 divided by 14/15? im stuck

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
5 0

Answer:

When you divide fractions, you multiply by the reciprocal, So, you would have 9/5 * 15/14 you can cancel,  and get 9/1 * 3/14, and end up with 27/14,

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Rebecca bought a desk for $70 she refinished it and sold it for a 20% profit? How much profit did she make? What price did she r
belka [17]

Answer:

she sold it for $84 and made $14

Step-by-step explanation:

take 20% of 70 add it to 70 and bam answer

6 0
2 years ago
Add the decimals represented by the models below.
Bad White [126]

Answer:

im sorry cant help

Step-by-step explanation:

8 0
2 years ago
A researcher obtained M = 27 for a sample of n = 36 scores selected from a population with µ = 30 and σ = 18. This sample mean c
dusya [7]

Answer:

True

Step-by-step explanation:

Given that:

M = 27, sample of n = 36 scores, µ = 30 and σ = 18.

The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the z score is positive, the raw score is greater than the mean and if the z score is negative the raw score is less than the mean. The z score is given as:

z=\frac{x-\mu}{\sigma}

Given that M = 27, this means that x = 27. Therefore:

z=\frac{x-\mu}{\sigma}\\\\for \ a\ sample\ size(n):z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\z=\frac{27-30}{18/\sqrt{36} } =\frac{-3}{3}=-1

This sample mean corresponds to a z-score of z = –1.00.

7 0
3 years ago
It's all politics: A politician in a close election race claims that 52% of the voters support him. A poll is taken in which 200
riadik2000 [5.3K]

Answer:

a) P(x ≤ 0.44) = 0.02275

b) The probability of obtaining a sample proportion less than or equal to 0.44 is very low (2.275%), hence, it would be unusual to obtain a sample proportion less than or equal to 0.44.

c) P(x ≤ 0.50) = 0.30854

A probability of 30.854% doesn't scream unusual, but it is still not a very high probability. So, it is still slightly unusual to obtain a sample proportion of less than half of the voters that don't support the politician.

Step-by-step explanation:

Given,

p = population proportion that support the politician = 0.52

n = sample size = 200

(np = 104) and [np(1-p) = 49.92] are both greater than 10, So, we can treat this problem like a normal distribution problem.

This is a normal distribution problem with

Mean = μ = 0.52

Standard deviation of the sample proportion in the distribution of sample means = σ = √[p(1-p)/n]

σ = √[0.52×0.48)/200]

σ = 0.035 ≈ 0.04

a) Probability of obtaining a sample proportion that is less than or equal to 0.44. P(x ≤ 0.44)

We first normalize/standardize/obtain z-scores for a sample proportion of 0.44

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (0.44 - 0.52)/0.04 = -2.00

To determine the probability of obtaining a sample proportion that is less than or equal to 0.44.

P(x ≤ 0.44) = P(z ≤ -2)

We'll use data from the normal probability table for these probabilities

P(x ≤ 0.44) = P(z ≤ -2) = 0.02275

b) Would it be unusual to obtain a sample proportion less than or equal to 0.44 if the politician's claim is true?

The probability of obtaining a sample proportion less than or equal to 0.44 is 0.02275; that is, 2.275%.

The probability of this occurring is very low, hence, it would be unusual to obtain a sample proportion less than or equal to 0.44.

c) If the claim is true, would it be unusual for less than half of the voters in the sample to support the politician?

Sample proportion that matches half of the voters = 0.50

P(x < 0.50)

We follow the same pattern as in (a)

We first normalize/standardize/obtain z-scores for a sample proportion of 0.50

z = (x - μ)/σ = (0.50 - 0.52)/0.04 = -0.50

To determine the probability of obtaining a sample proportion that is less than 0.50

P(x < 0.50) = P(z < -0.50)

We'll use data from the normal probability table for these probabilities

P(x < 0.50) = P(z < -0.50) = 1 - P(z ≥ -0.50) = 1 - P(z ≤ 0.50) = 1 - 0.69146 = 0.30854

Probability of obtaining a sample proportion of less than half of the voters that support the politician = 0.30854 = 30.854%

This value is still not very high, it would still he unusual to obtain such a sample proportion that don't support the politician, but it isn't as unusual as that calculated in (a) and (b) above.

Hope this Helps!!!

3 0
3 years ago
CAN SOMEONE PLEASE HELP ME!!!!!!!!!
wlad13 [49]

Answer:

12(m +1) > 18m - 3

12m + 12 > 18m - 3

12+3 > 18m - 12m

15 > 6 m.

m < 15/6

m < 2.5

4th option is correct.

7 0
3 years ago
Read 2 more answers
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