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GarryVolchara [31]
3 years ago
15

Name the property of real numbers illustrated by the equation.

Mathematics
1 answer:
Elden [556K]3 years ago
3 0
The -2 would be distributed to the x and the 4 making the equation -2x - 8. So, the answer is C.
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Suppose that in a random sample of size 200, standard deviation of the sampling distribution of the sample mean 0.08. researcher
sertanlavr [38]

Answer:

400

Step-by-step explanation:

The computation of the sample size needed is shown below:

Since at the sample size of 200 there is a standard deviation of 0.08

But when the standard deviation is 0.04 so the sample size is 400

As sample standard deviation would be inversely proportional to the square root of the sample size

7 0
3 years ago
Law of cosines: a2 = b2 + c2 – 2bccos(A) Which equation correctly applies the law of cosines to solve for an unknown angle measu
Cloud [144]
The law of cosines is used for calculating one side of the triangle if the angle opposite to that side is given as well as the other sides. For this problem, we are given angle B. Therefore, the correct answer among the choices given is option 1 where a is equal to 5 and c is equal to 3.
8 0
4 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
Here is 93 points but answer this please If x = 4, what is the value of x3 + x - 5?
Luda [366]

Answer:

11

Step-by-step explanation:

x3+x-5

3*4=12

12+4-5

16-5=11

pls i REALLY need brainliest

8 0
3 years ago
Three friends collected aluminum cans from the neighborhood to recycle in total they receive 300 cans many collected 90 Jim coll
spin [16.1K]

Given

Total cans = 300

Manny= 90

Jim =100

Bob=110

Now their percentage

Manny percentage

\begin{gathered} manny=\frac{90}{300}\times100\text{ \%} \\  \\ Manny\text{ percentage=}\frac{90}{3}\text{ \%} \\  \\ Manny\text{ percentage =30  \%} \end{gathered}

Jim Percentage

\begin{gathered} Jim=\frac{100}{300}\times100\text{ \%} \\ Jim\text{ percentage=}\frac{1}{3}\times100\text{  \%} \\ Jim\text{ percentage=33.333\%} \end{gathered}

Bob percentage

undefined

6 0
1 year ago
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