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sammy [17]
2 years ago
14

Line C passes through points (0, 2) and (8,8). What is the slope of a line parallel to line C?

Mathematics
1 answer:
balu736 [363]2 years ago
4 0

Answer:

below

Step-by-step explanation:

If line C is parallel to another line, they will have the same slope. so calculate the slope first:

8-2/8-0=3/4(simplified)

and thats it

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you are buying cherries at the grocery store if the cost is $4.25 per pound, create a relation that represenr the amount spent ,
Tom [10]
A = 4.25p

this equation says that the amount that you spent (A) is equal to the how many pounds of cherries you buy (p) and you know from the question that each pound costs 4.25
4 0
3 years ago
On Monday, Sarah has to meet her friend at the park after school The distance from her house to school is 2x+5 The distance from
DanielleElmas [232]

Answer:

8x + 4 - z

Step-by-step explanation:

Given the following :

The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her

Distance from house to school = 2x + 5

Distance from school to park = z

Total distance covered = 10x + 9

Distance from park to house =?

Total distance = (distance from house to school + distance from school to park + distance from park to house)

Let p = distance from park to house

10x + 9 = (2x + 5 + z + p)

10x + 9 - 2x - 5 - z = p

8x + 4 - z

6 0
3 years ago
Ok last question i asked was answered by a scam bot so here i go again
Daniel [21]

Answer:

Make 7 jumps, each 0.2 units long. You end at 1.4, which is the product of 7 and 0.2.

Sorry to hear about the bot! Hope this helps!

5 0
2 years ago
Grading managers. Some companies "grade on a bell curve" to compare the performance of their managers and professional workers.
Monica [59]

Answer:

\mu = 250, \sigma = 175.781

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the grades of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

For this case we have two conditions given:

P(X

P(X>475) = 0.1 or equivalently P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

So we can find a value from the normal standard distribution that accumulates 0.1 and 0.9 of the area in the left, for this case the two values are:

z= -1.28, z=-1.28

We can verify that P(Z<-1.28) =0.1[/tex] and P(Z<1.28) =0.9[/tex]

And then using the z score we have the following formulas:

-1.28 = \frac{25 -\mu}{\sigma}   (1)

1.28 = \frac{475 -\mu}{\sigma}   (2)

If we add equations (1) and (2) we got:

\frac{25 -\mu}{\sigma} + \frac{475 -\mu}{\sigma} =0

We can multiply both sides of the equation by \sigma and we got:

25+ 475 -2 \mu = 0

\mu = \frac{500}{2}= 250

And then we can find the standard deviation for example from equation (1) and we got:

\sigma = \frac{25-250}{-1.28}=175.781

So then the answer would be:

\mu = 250, \sigma = 175.781

 

3 0
3 years ago
The number of stamps that Kaye and Alberto had were in the ration of 5:3 respecctively. After Kaye gave Alberto 10 of her stamps
masha68 [24]

Answer:  The correct option is

(D) 60.

Step-by-step explanation:  Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.

After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.

We are to find the number of stamps that Kaye had more than Alberto.

Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.

Then, according to the given information, we have

(5x-10):(3x+10)=7:5\\\\\Rightarrow \dfrac{5x-10}{3x+10}=\dfrac{7}{5}\\\\\Rightarrow 25x-50=21x+70\\\\\Rightarrow4x=120\\\\\Rightarrow x=\dfrac{120}{4}\\\\\Rightarrow x=30.

So, the number of stamps that Kaye had = 5 × 30 = 150

and

the number of stamps that Alberto had = 3 × 30 = 90.

Therefore, the number of stamps that Kaye had more than Alberto is

150-90=60.

Thus, Kaye had 60 stamps more than Alberto.

Option (D) is CORRECT.

7 0
3 years ago
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