Xy = 45 (x+y)/2=7 --------- x+y = 14 Ah. So we can simplify the problem to, 'the product of two numbers is 45 and their sum is 14'. This shouldn't too hard to guess: the numbers are 5 and 9
Let the two numbers be x and y. Now, according to question x*y=45 (let this be eq1)and (x+y)/2=7(let this be eq2) x+y=14 x=14-y Putting this in eq1 (14-y)*y=45 14y-y^2=45 This is a quadratic equation y^2-14y+45=0 You can solve a quadratic any way you want. Here factorization method is being used. y(y-9)-5(y-9)=0 (y-5)(y-9)=0 y can be equal to 9 or 5 Using any of the y values we can find x by placing y in eq1 or 2[preferably 2 because addition] If y=5 then x=9 If y=9 then x=5
