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jeyben [28]
2 years ago
6

29. Which of the following expressions will result in a real answer after being simplified? Select all that apply.

Mathematics
1 answer:
nexus9112 [7]2 years ago
5 0

Answer: A, B, C, and E

Step-by-step explanation:

If both sides are real numbers, then the product will be a real number.

If in at least one of the sides we have a complex number, then the product will be real if:

The other number is zero.

The other number is the conjugate of the first.

This is when:

Suppose we have a number:

z = a + b*i

The conjugate will be:

w = a - b*i

And the product between them is:

(a + b*i)*(a - b*i) = a^2 + a*b*i - a*b*i + b^2 = a^2 + b^2

Then the options that will have a real answer are:

A. (4+5i)(4-5i) = 4^2 + 5^2 = 16 + 25 = 41

B. (4 + 91)*(41 - 9) = 3040

C. (3 + 2*i)*(3 -2*i) = 3^2 + 2^2 = 9 + 4 = 13

E. (312 + 7i)*(312 - 7i) = 312^2 + 7^2 = 97,393

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2 1/6 - (-8/3) + (-4 7/9) =
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Answer:

1/18

Step-by-step explanation:

First make it so they all have the same denominator.

So...

2 3/18 - (- 48/18) + (- 4 14/18)

Then we remove parenthesis...

2 3/18 +48/18 - 4 4/18

1/18

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Explain why 1 hundred 4 tens and 14 tens name the same number
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x= -1.7

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What is the value of x when the Richter scale rating is 7.9 round your answer to the nearest
Oksi-84 [34.3K]
If no base is stated, then assume base 10
log(x)=log_{10}(x)
rememer
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so
r=log(x) or
r=log_{10}(x) translates to 10^r=x

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4 0
3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
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