Answer: 3
Step by step explanation
I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

If we solve the first two equations for y squared, we have

And we can deduce

So that the third equation becomes

(we can't accept the negative root because negative lengths make no sense)
Answer:
Step-by-step explanation:
Given function is,
f(x) = 
If the given function is vertically stretched by a scale factor of
Or 1.5,
Transformed function will be,
h(x) = ![\frac{3}{2}[f(x)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bf%28x%29%5D)
h(x) = 
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) = 
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of
then shifted 1 unit upward.
Answer:
the triangles are in AA similarity.
Step-by-step explanation:
CB/DE = AB/AD
3/11 = x/9
cross multiply to get;
x = 2.45