We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
Answer:
C
Step-by-step explanation:
Given
6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation
6x + 24 = 2y + 10 ( subtract 10 from both sides )
6x + 14 = 2y ( divide all terms by 2 )
3x + 7 = y, hence
y = 3x + 7 → C
Answer:
z/8
Step-by-step explanation:
cuz it says z and 8 in that order so z/8 please dont just ignore give me 5 star and thanks dont ignore if u do i will never help you
Answer:
Point Form:
(0,4)
Equation Form:
x=0,y=4
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.