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exis [7]
3 years ago
6

Please help! These mathematics are very confusing. need help right away.

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
<span>
Exercise #1:
Point H = (–2, 2)
Point J = (–2, –3)
Point K = (3, –3)

It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it.  Then
you'd immediately see what's going on.

Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.

</span><span>Notice that points J and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.

Notice that point-J is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-J is one corner of the square.

H is another corner of the square.  It's 5 units above J.

K is another corner of the square.  It's 5 units to the right of J.

The fourth corner is (2, 3) ... 5 to the right of H,
                                       and 5 above K.
____________________________________

Exercise #2:
</span><span>Point H = (6, 2)
Point J = (–2, –4)
Point K = (-2, y) .

</span><span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it.  Then
you'd immediately see what's going on.

</span><span>Notice that points J and K have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.

We need K to connect to point-H in such a way that it's on
the same horizontal line as H.  Then the vertical and horizontal
lines that meet at K will be perpendicular, and we'll have the
right angle that we need there to make the right triangle.
So K and H need to have the same y-coordinate.
H is the point (6, 2).  So K has to be up at  (2, 2) .
____________________________________________

Exercise #3:
</span>
<span>Point H = (-6, 2)
Point J = (–6, –1)
Point K = (4, 2) .
</span>
<span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it.  Then
you'd immediately see what's going on.

This exercise is exactly the same as #1, except that it's a
rectangle instead of a square.  It's still make of horizontal
and vertical lines, and that's all we need to know in order
to solve it.</span><span>

Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.

</span><span>Notice that points H and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.

Notice that point-H is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-H is one corner of the rectangle.

J is another corner of the rectangle.  It's 3 units below H.

K is another corner of the square.  It's 4 units to the right of H.

The fourth corner is (2, -1) ... 4 to the right of J,
                                       and  3 below K.

</span>
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What is the true solution to the equation below?
Naddik [55]
Yeeee

assuming your equaiton is
2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)


remember some nice log rules
log_a(b)=c translates to a^c=b
and
a^{log_a(b)}=b
and
xlog_c(b)=log_c(b^x)
and
ln(x)=log_e(x)
and
log(a)-log(b)=log(\frac{a}{b})
and
if log(a)=log(b) then a=b

so

we can simplify a bit of stuff here

the e^{ln(2x)} \space\ and \space\ the \space\ e^{ln(10x)} can be simplified to 2x \space\ and \space\ 10x

so we gots now

2ln(2x)-ln(10x)=ln(30)
ln((2x)^2)-ln(10x)=ln(30)
ln(4x^2)-ln(10x)=ln(30)
ln(\frac{4x^2}{10x})=ln(30)
same base so
\frac{4x^2}{10x}=30
\frac{2x}{5}=30
times both sides by 5
2x=150
divide both sides by 2
x=75
answer is x=75
5 0
3 years ago
Find the ratio of 15 cm and 9 mm​
WITCHER [35]

Answer:

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4 0
3 years ago
Read 2 more answers
(ab² + 13b - 4a) + (3ab² + a +7b)
Natalija [7]

Answer:

4ab² + 20b - 3a

Step-by-step explanation:

This question most likely asks us to simplify the expression, as factoring is not possible...

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4 0
3 years ago
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GaryK [48]

Answer:

x = +√30

Step-by-step explanation:

Please write 30 = x squared as 30 = x^2.

If x^2 = 30, there are two solutions:  x = +√30 and x = -√30.

Several possible answers are given.    x=30−−√ is closest to the correct one, but must be written as x = √30.  Please ask someone how to find the "√" operator in Brainly.  Or, just write "sqrt(      )" instead.

6 0
3 years ago
Please help! <br><br> Which angle is a vertical angle with ZEFD?<br> - - - -
mixer [17]

Answer:

<AFB

Step-by-step explanation:

The angle that is a vertical angle with <EFD would be the angle that is vertically opposite and equal to <EFD.

Taking a look at the diagram, yiu would observe that <AFB is vertically opposite to <EFD. Therefore, <AFB is a vertical angle with <EFD.

6 0
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