<span> Exercise #1: Point H = (–2, 2) Point J = (–2, –3) Point K = (3, –3)
It would be very helpful if you could take a pencil and a piece of paper, and sketch a graph with these points on it. Then you'd immediately see what's going on.
Notice that points H and J have the same x-coordinate, but different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points J and K have different x-coordinates but the same y-coordinate, so they're on the same horizontal line.
Notice that point-J is on both the horizontal line and the vertical line, so the lines meet there, and they're perpendicular. Point-J is one corner of the square.
H is another corner of the square. It's 5 units above J.
K is another corner of the square. It's 5 units to the right of J.
The fourth corner is (2, 3) ... 5 to the right of H, and 5 above K. ____________________________________
Exercise #2: </span><span>Point H = (6, 2) Point J = (–2, –4) Point K = (-2, y) .
</span><span>It would be very helpful if you could take a pencil and a piece of paper, and sketch a graph with these points on it. Then you'd immediately see what's going on.
</span><span>Notice that points J and K have the same x-coordinate, but different y-coordinates, so they're on the same vertical line.
We need K to connect to point-H in such a way that it's on the same horizontal line as H. Then the vertical and horizontal lines that meet at K will be perpendicular, and we'll have the right angle that we need there to make the right triangle. So K and H need to have the same y-coordinate. H is the point (6, 2). So K has to be up at (2, 2) . ____________________________________________
Exercise #3: </span> <span>Point H = (-6, 2) Point J = (–6, –1) Point K = (4, 2) . </span> <span>It would be very helpful if you could take a pencil and a piece of paper, and sketch a graph with these points on it. Then you'd immediately see what's going on.
This exercise is exactly the same as #1, except that it's a rectangle instead of a square. It's still make of horizontal and vertical lines, and that's all we need to know in order to solve it.</span><span>
Notice that points H and J have the same x-coordinate, but different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points H and K have different x-coordinates but the same y-coordinate, so they're on the same horizontal line.
Notice that point-H is on both the horizontal line and the vertical line, so the lines meet there, and they're perpendicular. Point-H is one corner of the rectangle.
J is another corner of the rectangle. It's 3 units below H.
K is another corner of the square. It's 4 units to the right of H.
The fourth corner is (2, -1) ... 4 to the right of J, and 3 below K.
No we can consider A as single event. See the explanation below
Step-by-step explanation:
Let's define the event A as:
A=" Select a 4 from a standard deck of 52 cards"
We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.
And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.