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aalyn [17]
3 years ago
9

Solve by factoring: X^2-13x-14=0

Mathematics
1 answer:
AURORKA [14]3 years ago
4 0

Answer:

x = -1 and x= 14

Step-by-step explanation:

x^2 -13x -14=0

x^2 + x- 14x -14 = 0

x(x+1) -14(x+1) = 0

(x+1)(x-14) =0

x+1 = 0

x= -1

x-14=0

x= 14

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I need help with this, please!
Vera_Pavlovna [14]

Option D: x \geq 3 is the solution

Explanation:

The given expression is 3 x-1 \geq 8

We need to determine the solution of the expression.

<u>Solution:</u>

The solution of the expression can be determined by solving the expression for the variable x.

Thus, we have,

3 x-1 \geq 8

Adding both sides of the expression by 1, we get,

3x\geq 9

Dividing both sides of the expression by 3, we get,

x \geq 3

Thus, the solution of the expression is x \geq 3

Hence, Option D is the correct answer.

6 0
3 years ago
Please please help im confused again
timama [110]

Answer:

A_s=179  \ yd

Step-by-step explanation:

Area of Circle can be calculated using following formula

A=\pi r^{2}

Where r is radius of circle

<u>Area of outer circle (r=11 yd)</u>

A_1=\pi (11)^{2}\\A_1=379.94 \ yd

<u>Area of inner circle (r=8 yd)</u>

A_2=\pi (8)^{2}\\A_2=200.96 \ yd

Area of shaded region

A_s=A_1-A_2

A_s=379.94-200.96\\A_s=179  \ yd

3 0
3 years ago
Chuck and Blaire decided to share a 10
klemol [59]

Answer:

A. 7 1/6

Step-by-step explanation:

10 3/4 * 2/3=

43/4 * 2/3= 86/12

86/12 = 7 2/12 = 7 1/6

3 0
3 years ago
Find the coordinates of the orthocenter for XYZ with X(-5,-1) Y(-2,4), Z(3,-1)
V125BC [204]

9514 1404 393

Answer:

  (-2, 2)

Step-by-step explanation:

The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.

Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...

  x = -2

__

Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...

  y -(-1) +(1)(x -(-5))

  y = x +4 . . . . . . . . subtract 1 and simplify

The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...

  y = (-2) +4 = 2

The orthocenter is (x, y) = (-2, 2).

4 0
3 years ago
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