Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
Answer:
53 feet
Step-by-step explanation:
if you start with 62 feet and add 39 feet because he went down 62+39 you get 101 then if you subtract 48 because he went up, 101-48 you get 53 feet
Answer:
A, f(2) is the answer because it fits into the requirements.
Answer:
-9
Step-by-step explanation:
Using the sum/difference property of logarithms, we can rewrite the expression given as:
log b^3 + log c^3 - log √(a^3) --> log √(a^3) can also be written as log a^1.5
Next, we can use the power property of logarithms, and rewrite it again as:
3log b + 3log c - 1.5log a
Now, we can substitute the values of log a, log b, and log c:
3(11) + 3(-9) - 1.5(10)
33 - 27 - 15
-9
Simplifying, we get -9 as the answer.