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3 years ago

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A car travels at a speed of 55 kilometers per hour.Find the distance travelled by the car in 12 minutes and 30 seconds.Find the

Answers in meters

1 answer:

never [62]3 years ago

4 0

Answer:

Step-by-step explanation:

(distance) d = (speed) s * t (time)

= 55km/h * 12.30m/s

= 11.275 km

= 11.275 * 1000

= 11275m

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Using the given points, determine the slope. (0, 32) and (100, 212)

Colt1911 [192]

Slope=m=y/x=rise/run=(y1-y2)/(x1-x2)
Labeling the question; 0=x1, 32=y1, 100=x2, 212=y2
so just go ahead and fill the numbers in;
(32-212)/(0-100)=(-180/-100)=1.8
so therefore, the slope is at 1.8

3 0

3 years ago

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Pleaseeeee help 50 points + brainliest mark

natka813 [3]

Answer:

A

Step-by-step explanation:

3 0

2 years ago

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m_a_m_a [10]

Answer:

question no proper plz give question in right way

5 0

2 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?

Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

$A = \pi r^2$

where r = radius of the circle

The area of a sector of a circle is given as:

$A_s = \frac{\alpha }{2\pi} * \pi r^2$

where α = central angle in radians

Since $\pi r^2$ is the area of a circle, A, this implies that:

$A_s = \frac{\alpha }{360} * A$

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

$33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi$

The area of the circle is 36π.

5 0

3 years ago

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