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4 years ago

Write 10 5/12 as an equivalent improper fraction.

1 answer:

3 0

To get the improper fraction of 10 5/12, multiply the denominator of the fraction and the number on the left which is 10x12=120.

Then you want to add the numerator 5 to 120 to get 125.

Using the denominator 12, and the numerator 125, there is your answer. 125/12.
Hope it wasn't too confusing..
Hope this helped :)

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In the triangle above, the cosine of a is 0.8.What is sine of b?

Natalka [10]

Answer:

sin b = 0.8

Step-by-step explanation:

Since a and b are complementary angles , then

sin b = cos a = 0.8

5 0

3 years ago

8% as a fraction in simplest form

masha68 [24]

Answer: 2/25

Step-by-step explanation:

8% means 8/100

To reduce to the simplest fraction, divide through with a common factor of 4

Divide numerator by 4 = 2

Divide denominator by 4 = 25

Therefore, 8% = 2/25

I hope this helps.

3 0

3 years ago

Fill in the missing fraction or mixed number __ + 1/4 = 5/8

gogolik [260]

3/8=answer

1) 5/8-1/4=

2) (5•4)-(1•8)=

8•4

3) 20-8

32 =

4) 12

32=

5) 12/4

32/4=

6) 3

8 =answer

5 0

3 years ago

Somebody please explain this I have a major exam soon and I really need to know how to solve problems like this

nevsk [136]

Answer:

y = 2x - 3

Step-by-step explanation:

Step 1: Find the slope. You find the slope by using the formula y2-y1/x2-x1. (2, 1) and (4, 5) are our points. Let's find our values.

y2= 5

y1= 1

x2 = 4

x1 = 2

Plug in the numbers into the equation. 5 - 1 is 4. 4 - 2 is 2. 4/2 is 2. There. Our slope is 2.

Step 2: Find the b value. Keep in mind that an equation in point-slope form is y = mx + b, where m = the slope, and b = the y-intercept. For this part, you will plug in one of the points as x and y to find the b value. let's use point (4, 5)

The equation then becomes 5 = 2(4) + b. As we know, 2 * 4 is 8. Subtract 8 on both sides of the equation to cancel out the right side and isolate the b variable. 5 - 8 is -3. Even if you use the other point for the equation (1 = 2(2) +b), you should get the same answer of -3.

5 0

3 years ago

38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy

lina2011 [118]

It looks like the integral is

$\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy$

where C is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing C. Let x = 2 cos(t ) and y = 2 sin(t ), with 0 ≤ t ≤ 2π. Then

$\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}$

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on C nor in the region bounded by C, so

$\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy$

where D is the interior of C, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: $-2\times \pi\times2^2 = -8\pi$ .

3 0

3 years ago