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noname [10]
3 years ago
6

Find the work done by a force of 4 pounds acting in the direction of 41° to the horizontal in moving an object 5 feet from (0, 0

) to (5, 0).
A. 13.1 ft-lb
B. 16.2 ft-lb
C. 15.1 ft-lb
D. 30.2 ft-lb
Mathematics
1 answer:
babymother [125]3 years ago
6 0
F = 5 p
d = 5 ft
The work formula:  
W = F * d 
W = 5 p * cos 41° * 5 ft = 4 * 0.75471 * 5 = 15.09 ft-lb ≈ 15.1 ft-lb
Answer: C  ) 15.1 ft-lb
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KengaRu [80]

Answer:

Part 1) Triangle GHI, JKL

Part 2) (40*15)and(8*3), (18*6)and(4.5*1.5)

Step-by-step explanation:

we know that

If two figures are similar

then

the ratio of their corresponding sides are equal and is called the scale factor

Part 1)

<u>case a)</u> triangle GHI

If ABC and GHI are similar

then

\frac{4}{24}=\frac{3}{7}=\frac{5}{25}

but

0.17 \neq 0.43 \neq \ 0.20

therefore

Triangle GHI is not similar to triangle ABC

<u>case b)</u> triangle DEF

If ABC and DEF are similar

then

\frac{4}{44}=\frac{3}{33}=\frac{5}{55}

0.09=0.09=0.09

therefore

Triangle DEF is similar to triangle ABC

<u>case c)</u> triangle MNO

If ABC and MNO are similar

then

\frac{4}{10}=\frac{3}{7.5}=\frac{5}{12.5}

0.4=0.4=0.4

therefore

Triangle MNO is similar to triangle ABC

<u>case d)</u> triangle JKL

If ABC and JKL are similar

then

\frac{4}{21}=\frac{3}{20}=\frac{5}{29}

0.19 \neq 0.15 \neq 0.17

therefore

Triangle JKL is not similar to triangle ABC

Part 2)

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\frac{40}{8}=\frac{15}{3}

5=5

therefore

the rectangles are similar

case b) If the rectangles are similar, then

\frac{18}{4.5}=\frac{6}{1.5}

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therefore

the rectangles are similar

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\frac{1,225}{3.5}=\frac{144}{1.2}

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therefore

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\frac{13}{5.2}=\frac{5}{2.5}

2.5\neq 2

therefore

the rectangles are not similar


3 0
4 years ago
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