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Solnce55 [7]
2 years ago
13

3. Janice raked leaves for 4 hours and

Mathematics
2 answers:
34kurt2 years ago
8 0

Answer:

£7.50 per hour

answer: c

Step-by-step explanation:

hope this helps!

have a good day :)

scZoUnD [109]2 years ago
5 0
Answer is c 7.50 per hour
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This is a linear equation/ graph quiz ! please help , my teacher makes no sense to me!
JulijaS [17]

Answer:

(8,5)

Step-by-step explanation:

5x - 2y = 30

coordinates are (x,y) so you plug in 8 for x and solve for y

5(8) - 2y = 30

40 - 2y = 30

subtract 40 from both sides to isolate y

-2y = -10

divide both sides by -2 to isolate y

y = 5

6 0
3 years ago
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vovikov84 [41]

Answer:

sorry


Step-by-step explanation:


3 0
3 years ago
a population of rabbits triple every month. the population starts with two rabbits. how many are there after three months?
Lera25 [3.4K]
2 x 3 = 6
6 x 3 = 18
18 x 3 = 54 

The answer is 54

6 0
3 years ago
A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

5 0
3 years ago
What do you call a person who makes faces all day long
lana66690 [7]
Longface
longface
longface
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