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vodka [1.7K]
3 years ago
5

Which equation represents a line that passes through (4,1/3 ) and has a slope of 3/4?

Mathematics
2 answers:
Maru [420]3 years ago
3 0

Answer:

22 is the jsksnenekeond snLL

BlackZzzverrR [31]3 years ago
3 0

Answer: The answer is B

Step-by-step explanation:

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x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4

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511 = -7 (10x – 13)<br> steps
PilotLPTM [1.2K]

Answer: x=-6

<u>Simplify both sides of the equation</u>

<u></u>511=(-7)(10x)+(-7)(-13)(Distribute)\\511=-70x+91<u></u>

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<u>Flip the equation</u>

<u></u>-70x+91=511<u></u>

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<u>Subtract 91 from both sides</u>

<u></u>-70x+91-91=511-91\\-70x=420<u></u>

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3 years ago
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An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

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4 years ago
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