Write in Slope-intercept Form an equation of the line that passes through the given points.

Which of the diagrams below represents the statement if it is a rectangle, then it is a square

Naily [24]

All the rectangle are square if length becomes equal to breath !

4 0

3 years ago

Factor 2x^2 - 6x + 4 completely

katovenus [111]

Answer:

Step-by-step explanation:

Factor

2

out of

2

x

2

.

2

(

x

2

)

+

6

x

−

4

Factor

2

out of

6

x

.

2

(

x

2

)

+

2

(

3

x

)

−

4

Factor

2

out of

−

4

.

2

x

2

+

2

(

3

x

)

+

2

⋅

−

2

Factor

2

out of

2

x

2

+

2

(

3

x

)

.

2(

x

2

+

3

x

)

+

2

⋅

−

2

Factor

2

out of

2

(

x

2

+

3

x

)

+

2

⋅

−

2

.

2

(

x

2

+

3

x

−

2

)

6 0

3 years ago

Read 2 more answers

Find 8 and one third percent of 144

madam [21]

$\bf 8\frac{1}{3}\implies \cfrac{8\cdot 3+1}{3}\implies \cfrac{25}{3}
\\\\\\
now\qquad \cfrac{\frac{25}{3}}{100}\implies \cfrac{\frac{25}{3}}{\frac{100}{1}}\implies \cfrac{25}{3}\cdot \cfrac{1}{100}\implies \cfrac{1}{3\cdot 4}\implies \cfrac{1}{12}
\\\\\\
8\frac{1}{3}\%\ of\ 144\implies \left( \cfrac{\frac{25}{3}}{100} \right)\cdot 144\implies \cfrac{1}{12}\cdot 144\implies \cfrac{144}{12}\implies 12$

3 0

3 years ago

Select all equations whose graphs have a vertex with x-coordinate 2

iren2701 [21]

Answer:

C

Step-by-step explanation:

because you have to foil then do -b/2a

8 0

3 years ago

For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df

rjkz [21]

Answer:

a) For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

b) For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

$t_{\alpha/2} =\pm 2.35$

Part b

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

$t_{\alpha/2} =\pm 2.62$

3 0

3 years ago