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Viktor [21]
3 years ago
12

According to the manufacturer, about 31% of chewy candy in a package of Cherry's Chews are strawberry. What is the probability t

hat the first strawberry candy chosen from a bag will be, at LEAST, the fourth candy chosen overall?
Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

0.3285

Step-by-step explanation:

This problem involves Geometric probability distribution because experiment is repeated different number of times until success is achieved.

we have to find P(X≥4). It can be written as P(X≥4)=1-P(X<4)=1-P(X≤3)

P(X≤3)=?

Using Geometric probability distribution

P(X=n)=p^x*q^n-1

P(X≤3)=P(X=1)+P(X=2)+P(X=3)

Here p=0.31,

P(X≤3)=0.31^1*0.69^0+0.31^2*0.69^1+0.31^3*0.69^2)=0.6715

P(X≥4)=1-P(X≤3)=1-0.6715=0.3285

The probability that the first strawberry candy chosen from a bag will be, at LEAST, the fourth candy chosen overall is 32.85%.

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X-30+x-30+x=180

3x-60=180

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6 0
3 years ago
#7-9 please help with an explanation,, will mark brainliest
Mandarinka [93]

Answers:

<h2>7. 12</h2><h2>8. -√18</h2><h2>9. √220</h2>

Step-by-step explanation:

To find out which is greater, we must eliminate the radical symbol.

#7

\sqrt{88} = 9.38083151965

9.4 < 12

#8

-\sqrt{18} = -4.24264068712

-4.2 > -6

#9

\sqrt{220} = 14.8323969742

14.5 < 14.8

I'm always happy to help :)

8 0
3 years ago
Please help me out with this question
oee [108]
The answer is B cause you add 6 and 2
4 0
3 years ago
The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 118 inches, find the
IgorLugansk [536]
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
6 0
3 years ago
How do the values in Pascal’s triangle connect to the coefficients?
damaskus [11]

Explanation:

Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.

If you consider what happens when you multiply out the product (a +b)^n, you can see where the coefficients nCk come from. For example, consider the cube ...

  (a +b)^3 = (a +b)(a +b)(a +b)

The highest-degree "a" term will be a^3, the result of multiplying together the first terms of each of the binomials.

The term a^b will have a coefficient that reflects the sum of all the ways you can get a^b by multiplying different combinations of the terms. Here they are ...

  • (a +_)(a +_)(_ +b) = a·a·b = a^2b
  • (a +_)(_ +b)(a +_) = a·b·a = a^2b
  • (_ +b)(a +_)(a +_) = b·a·a = a^2b

Adding these three products together gives 3a^2b, the second term of the expansion.

For this cubic, the third term of the expansion is the sum of the ways you can get ab^2. It is essentially what is shown above, but with "a" and "b" swapped. Hence, there are 3 combinations, and the total is 3ab^2.

Of course, there is only one way to get b^3.

So the expansion of the cube (a+b)^3 is ...

  (a +b)^3 = a^3 + 3a^2b +3ab^2 +b^3 . . . . . with coefficients 1, 3, 3, 1 matching the 4th row of Pascal's triangle.

__

In short, the values in Pascal's triangle are the values of the number of combinations of n things taken k at a time. The coefficients of a binomial expansion are also the number of combinations of n things taken k at a time. Each term of the expansion of (a+b)^n is of the form (nCk)·a^(n-k)·b^k for k =0 to n.

6 0
3 years ago
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