3 years ago

what are some key words, other than less and greater, that would indicate you need to use an inequality?

Mathematics

1 answer:

Paladinen [302]3 years ago

8 0

Equal to is under is fewer has maximum value is over is at most

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I' don't know how to do it can u help me plssssssss

vagabundo [1.1K]

the answer is 5 bebe. remember to use pemdas

p-parenthesis

e-exponents

m-multiplication

d-division

a-addition

s-subtraction

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2 years ago

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A psychology professor at a university is interested in determining the proportion of undergraduate students at her university w

mario62 [17]

Answer:

No, because the professor’s question had 3 possible answers

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2 years ago

Find a formula for the nth term of the sequence 1 -4 9 -16 25

ZanzabumX [31]

X² n = 1,2,3,4,5

1² = 1
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3 years ago

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

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3 years ago

Can someone help me solve this equation 5-x=12

RSB [31]

In order to solve you get x by itself:
5-x=12
-5 -5
-x=7
divide by negative 1

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2 years ago