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3 years ago

10

the vet sya that lena's puppy will grow to be at most 28 inches tall. lena's puppy is currently 1 foot tall. how many more inche

s will the puppy grow?

1 answer:

aliya0001 [1]3 years ago

4 0

16 more inches. 1 foot is equal 12 inches. 28-12=16

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Write an equation of the line that passes through (2, -5) and is parallel to the line 2y = 3x + 10.

Leto [7]

Answer:

Use the given slope and point to substitute into the point-slope formula y−y1=m(x−x1).

Slope-intercept form:

y=3x²+4x−25

Point-slope form:

y+5=(3x+10)⋅(x−2)

Step-by-step explanation:

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2 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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2 years ago

Sergio039 [100]

The answer is 9 cubic units

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2 years ago

kobusy [5.1K]

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This equation is used to calculate the quantity of lemonade.

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2 years ago

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Dmitriy789 [7]

♡ x is 57 degress

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2 years ago