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Nesterboy [21]
2 years ago
7

1. What is the ratio of black to white squares? (1 mark) I

Mathematics
2 answers:
irakobra [83]2 years ago
8 0
<h2>Answer:</h2>

2 : 4

<h3>Simplified Answer:</h3>

1 : 2

<h3>Step-by-step explanation:</h3>

black to white squares

theirs <u>2 black</u> squares and <u>4 whites</u>

put 2 first because its (black) to white

so we would have 2 : ? now we add the four to the other side

now we have <u>2 : 4</u>

to simplify it we can half <u>both</u> sides witch will get us <u>1 : 2</u>

<u></u>

<h3>Note:</h3><h3>Hope it helps!</h3><h3 />
kati45 [8]2 years ago
6 0

im sure it would be 2:4. if it was to be simplified it would be 1:2

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Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7
photoshop1234 [79]
Hope I can be of assistance!

3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \  \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}
3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \  3b^{-5}b^2c^{-4}c^7

\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \  b^{-5}b^2=\:b^{2-5}=\:b^{-3}
3b^{-3}c^{-4}c^7

\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \  c^{-4}c^7=\:c^{-4+7}=\:c^3
3b^{-3}c^3

\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \  b^{-3}=\frac{1}{b^3} \ \textgreater \  3\cdot \frac{1}{b^3}c^3

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{1\cdot \:3c^3}{b^3}

Finally
\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{3c^3}{b^3}

Hope this helps!
8 0
3 years ago
How much lemon juice did Damon use in the lemonade
OverLord2011 [107]

from the picture in every cup there are 1/5 of lemon + 4/5 of water.

the cups are 20

so 1/5 * 20 = 4

4 cup of lemon

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Step-by-step explanation:

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brilliants [131]

Answer:

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Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

m\angle 9 =80^\circ\\m\angle 5 =55^\circ

m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\

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Also

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4 0
3 years ago
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aniked [119]
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Etc.
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