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ludmilkaskok [199]
2 years ago
10

Find the area of the sector

Mathematics
1 answer:
Setler [38]2 years ago
6 0

Answer:

10:

7/4π = 5.5(1decimql place)

11:

50π = 157.1(1 decimal place)

Step-by-step explanation:

the equation is (angle/360) X πr^2

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The right triangle on the right is a scaled copy of the right triangle on the left. Identify
AlekseyPX

Answer:

scale factor is 1:3.5

Step-by-step explanation:

56/16 = 3.5

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Step-by-step explanation:

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7 0
2 years ago
16% of 130 is what number
earnstyle [38]
130 • .16 = 20.8 or 20 (4/5) or 104/5
Put the answer as 20.8 unless specified otherwise.
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5 0
3 years ago
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A<br> 19 = 548 and a<br> 33 = 968<br> Find a<br> 27
s2008m [1.1K]

Answer:

The value of a₂₇ is 788

Step-by-step explanation:

a₁₉ = 548

a₃₃ = 968

Now,

a₁₉ = 548 can be written as

a + 18d = 548 ...(1) and

a₃₃ = 968 can be written as

a + 32d = 968 ...(2)

Now, from equation (2) we get,

a + 32d = 968

a + 18d + 14d = 968

548 + 14d = 968 (.°. <u>a + 18d = 548</u>)

14d = 968 - 548

14d = 420

d = 420 ÷ 14

d = 30

Now, for the value of a put the value of d = 30 in equation (1)

a + 18d = 548

a + 18(30) = 548

a + 540 = 548

a = 548 - 540

a = 8

Now, For a₂₇

a₂₇ = a + 26d

a₂₇ = 8 + 26(30)

a₂₇ = 8 + 780

a₂₇ = 788

Thus, The value of a₂₇ is 788

<u>-TheUnknownScientist</u>

4 0
3 years ago
A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches
harkovskaia [24]

9514 1404 393

Answer:

  a) w(4w-15)

  b) w²

  c) w(4w -15) = w²

  d) w = 5

  e) 5 by 5

Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

__

b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

__

c) Equating the expressions for area, we have ...

  w(4w -15) = w²

__

d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

__

e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

4 0
3 years ago
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