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I am Lyosha [343]
3 years ago
12

At Mr. Hynd's ranch, there are 35 chickens and 20 cows. What is the ratio of the number of cows to the number of chickens at Mr.

Hynd's ranch?
Mathematics
1 answer:
elixir [45]3 years ago
5 0
The ratio is 20:35 or 20 to 35 and also 20/35, there are multiple ways to write it. My personal favorite is the first one but it depends on what your teacher wants!
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The graph of 15x + 7y = 15 is shown on the grid. Which ordered pair is in the solution set of 15x + 7y ≥ 15?
elena55 [62]

Answer:

The correct option is c.

Step-by-step explanation:

The given equation is

15x+7y=15

The given inequality is

15x+7y\geq 15

A point will contained in solution set if the above inequality satisfied by that point.

Check the point (0,-3),

15(0)+7(-3)\geq 15

-21\geq 15

This statement is false, therefore option a is incorrect.

Check the point (-3,0),

15(-3)+7(0)\geq 15

-45\geq 15

This statement is false, therefore option b is incorrect.

Check the point (3,3),

15(3)+7(3)\geq 15

66\geq 15

This statement is true, therefore option c is correct.

Check the point (-3,-3),

15(-3)+7(-3)\geq 15

-66\geq 15

This statement is false, therefore option d is incorrect.

7 0
3 years ago
Please help thank you asap
miss Akunina [59]
34 is the correct answer
3 0
3 years ago
Which number line shows the solution to 11x + 14 < –8?
Alika [10]

Answer:

positive 11x+ positive 14 to the right is greater than negative 8 to the left

Step-by-step explanation:

hope I helped

4 0
3 years ago
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If David has test average of 80, Homework average of 90, and the final exam score of 71,
kumpel [21]
B bc that math adds up right
7 0
3 years ago
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A Halloween trick-or-treat group consists of 3 Trolls, 4 Nazguls, 4 Ents, and 5 Pokemon. A committee of 4 is to be picked to rep
balu736 [363]

Answer:

The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357        

Step-by-step explanation:

No. of Trolls = 3

No. of  Nazguls =4

No. of Ents = 4

No. of Pokemon = 5

Total Monsters = 16

We are given that A committee of 4 is to be picked to represent the group at the Monster Bash.

(a) Find the probability that the committee will consist of 1 from each type of monster.

So, the probability that the committee will consist of 1 from each type of monster:

= \frac{^3C_1 \times ^4C_1 \times ^4C_1 \times ^5C_1}{^{16}C_4}

= \frac{\frac{3!}{1!(3-1)!} \times \frac{4!}{1!(4-1)!} \times \frac{4!}{1!(4-1)!}\times \frac{5!}{1!(5-1)!}}{\frac{16!}{4!(16-4)!}}

= \frac{\frac{3!}{1!(2)!} \times \frac{4!}{1!(3)!} \times \frac{4!}{1!(3)!}\times \frac{5!}{1!(4)!}}{\frac{16!}{4!(12)!}}

= 0.1318

b)Suppose that the Pokemon refuse to be on the same committee as a the Trolls.

So,  the probability that this type of committee is formed

= \frac{(^3C_3 \times ^8C_1)+(^3C_2 \times ^8C_2)+(^3C_1 \times ^8C_3)+(^3C_0 \times ^8C_4)+(^5C_4 \times ^8C_0)+(^5C_3 \times ^8C_1)+(^5C_2 \times ^8C_2)+(^5C_1 \times ^8C_3)}{^{16}C_4}

= \frac{(\frac{3!}{3!(3-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{3!}{2!(3-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{3!}{1!(3-1)!} \times\frac{8!}{3!(8-3)!})+(\frac{3!}{0!(3-0)!} \times \frac{8!}{4!(8-4)!})+(\frac{5!}{4!(5-4)!} \times \frac{8!}{0!(8-0)!})+(\frac{5!}{3!(5-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{5!}{2!(5-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{5!}{1!(5-1)!} \times \frac{8!}{3!(8-3)!})}{\frac{16!}{4!(16-4)!}}

= 0.5357

Hence The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357          

4 0
3 years ago
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