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Alenkinab [10]
3 years ago
14

Eric jogged for 47 minutes, ending at 3:35 p.m. When did Eric start his jog?

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

im pretty sure its c

Step-by-step explanation:

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The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion
Vanyuwa [196]

Answer:

Find the slope of the line that passes through the points shown in the table.

The slope of the line that passes through the points in the table is

.

Step-by-step explanation:

8 0
3 years ago
1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help
Gnesinka [82]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify :- 1 + - w² + 9w.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\large \sf1 + - w ^ { 2 } + 9 w

Quadratic polynomial can be factored using the transformation \sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where \sf x_{1} and x_{2} are the solutions of the quadratic equation \sf \: ax^{2}+bx+c=0.

\large \sf-w^{2}+9w+1=0

All equations of the form \sf\:ax^{2}+bx+c=0 can be solved using the quadratic formula: \sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)}  \\

Square 9.

\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)}  \\

Multiply -4 times -1.

\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)}  \\

Add 81 to 4.

\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)}  \\

Multiply 2 times -1.

\large \sf \: w=\frac{-9±\sqrt{85}}{-2}  \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is plus. Add -9 to \sf\sqrt{85}.

\large \sf \: w=\frac{\sqrt{85}-9}{-2}  \\

Divide -9+ \sf\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is minus. Subtract \sf\sqrt{85} from -9.

\large \sf \: w=\frac{-\sqrt{85}-9}{-2}  \\

Divide \sf-9-\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}}  \\

Factor the original expression using \sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \sf\frac{9-\sqrt{85}}{2}for \sf\:x_{1} and \sf\frac{9+\sqrt{85}}{2} for \sf\:x_{2}.

\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}

<h3>NOTE :-</h3>

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

\large \sf \: 1 + -  w {}^{2}  + 9w \\  =\large  \boxed{\bf \: 1 -  {w}^{2}   + 9w}

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0
2 years ago
There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an
vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

C =100 -50\\C= 50\ students

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

D =110 -50\\C= 60\ students

The number of students that have taken a course in either calculus or discrete mathematics is:

E = C+D = 50+60\\E= 110\ students

7 0
3 years ago
A boy jogs 250 meters in 110 seconds. What is his average speed in m/s?
murzikaleks [220]

250m/110s

25m/11s

25/11 m/s

6 0
3 years ago
Solve the equation.
elena55 [62]

Answer:

C: x=-3 or x=4

Step-by-step explanation:

To solve the equation x^2-x-12=0 we need to factor it

We are looking for two numbers that when multiplied give -12 and when added give -x

This means that when factored, the equation would be (x-4)(x+3)=0

Now we can set each of these equal to 0, which means that at

x=-3 and x=4 , the equation will equal 0

4 0
3 years ago
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