All categories

3 years ago

Please help asap. Very lost and confused

Mathematics

2 answers:

Ivenika [448]3 years ago

5 0

Look at a torial so you can have help

posledela3 years ago

4 0

The answer will be c

You might be interested in

Select 3 expressions that have a sum or difference of 3 /4 .

cupoosta [38]

Answer:

The Three expressions that have a sum or difference of 3 /4 .

B . 11/12 − 1/6

C. 3/5 + 3/20

E . 2/3 + 1/12

Step-by-step explanation:

The Three expressions that have a sum or difference of 3 /4 .

are

B . 11/12 − 1/6

$\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{11}{12}-\dfrac{1\times 2}{6\times 2}\\\\\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{11}{12}-\dfrac{2}{12}=\dfrac{11-2}{12}=\dfrac{9}{12}=\dfrac{3}{4}$

Therefore,

$\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{3}{4}$

C. 3/5 + 3/20

$\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{3\times 4}{5\times 4}+\dfrac{3}{20}\\\\\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{12}{20}+\dfrac{3}{20}=\dfrac{15}{20}=\dfrac{3}{4}$

Therefore,

$\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{3}{4}$

E . 2/3 + 1/12

$\dfrac{2}{3}+\dfrac{1}{12}=\dfrac{2\times 4}{3\times 4}+\dfrac{1}{12}\\\\\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{8+1}{12}=\dfrac{9}{12}=\dfrac{3}{4}$

Therefore,

$\dfrac{2}{3}+\dfrac{1}{12}=\dfrac{3}{4}$

7 0

3 years ago

Plz answer question fast

Bas_tet [7]

Answer:

OSMOSIS AND GIVE ME BRAINLIIST

8 0

3 years ago

The Venn Diagram shows a universe with 26 elements and two different outcomes: B and Y

Nutka1998 [239]

1. B and Y are 2 events,and Y has already occurred.

2. P(B|Y)=P(B∩Y)/P(Y),

gives the probability of B to occur, once Y has already happened.

3. According to the givens (check the diagram at the bottom, of the described problem),

P(B∩Y)=n(B∩Y)/n(U)=8/26=4/13

P(Y)=n(Y)/n(U)=12/26=6/13

P(B|Y)=P(B∩Y)/P(Y)=(4/13)/(6/13)=4/6=2/3=0.67

7 0

3 years ago

Read 2 more answers

Damian needs to buy 5 pints of juice. The store does not sell juice in pints, so Damian buys 3 quarts of Which statement is true

jenyasd209 [6]

Damian buys the quarts and splits them up into pints

8 0

4 years ago

Read 2 more answers

The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A

vekshin1

Answer:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

Step-by-step explanation:

Information provided

$\bar X= 15.7$ represent the sample mean for the usage of electricity

$\mu$ population mean (variable of interest)

$\sigma= 2.3$ represent the population standard deviation

n=1731 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula if we know the population deviation:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level provided is 0.99 or 95%, the value of significance is $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

And replacing we got:

$15.7-2.58\frac{2.3}{\sqrt{1731}}=15.6$

$15.7+2.58\frac{2.3}{\sqrt{1731}}=15.8$

We are 99% confident that the true mean of electricity comsumption is between (15.6 and 15.8) kWh

7 0

4 years ago