Answer:
b<-21
Step-by-step explanation:
1/3b+1<-6
1/3b<-7
*3 *3
b<-21
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
66
Step-by-step explanation:
(5 - 3)⁴ - 2(7) + 8²
PEMDAS
Parentheses first
(2)⁴ - 2(7) + 8²
Exponents
16 - 2(7) + 64
Multiply and divide from left to right
16 -14 +64
Add and subtract from left to right
2+64
66
<span>quotient of 63 and a number h would be 63/h
14 less than that would be 63 over h - 14
</span>
Second one
<span>7/21
Hope it helps
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