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STatiana [176]
3 years ago
5

Which expression represents the product of s and 39?A=39-sB=39÷sC=39sD=39+s​

Mathematics
1 answer:
Degger [83]3 years ago
4 0
The answer would be c because it means Multiply and whenever a variable is next to a number in this case 39s then that means it a multiplication
So C. 39s
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Suppose the position of an object moving horizontally after t seconds is given by the following functions s=f(t), s equals f , o
Scilla [17]

Answer:

(a) The graph of position function is shown below.

(b) The velocity function is v(t)=-2t+4 and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c) Velocity and acceleration of the object at t=1 are 2 and -2 respectively.

(d) The acceleration of the object is -2 when its velocity is zero.

(e) The speed is not increasing at any interval because the acceleration is constant.

Step-by-step explanation:

(a)

The given function is

f(t)=-t^2+4t-3; 0\leq t\leq 5

The position of an object moving horizontally after t seconds is given by

s=f(t)=-t^2+4t-3

The graph of position function is shown below.

(b)

Differentiate the position function with respect to time to find the velocity function.

v=f'(t)=-2t+4

Put v=0 to find the time when the object is stationary.

0=-2t+4

2t=4

t=2

The object is stationary at t=2 because the velocity of the object is 0 at t=2.

The velocity function is v(t)=-2t+4 and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c)

The velocity function is

v=f'(t)=-2t+4

Substitute t=1 in the above function.

v=f'(1)=-2(1)+4=2

Differentiate the velocity function with respect to time to find the acceleration function.

a=f''(t)=-2

Substitute t=1 in the above function.

a=f''(1)=-2

Therefore the velocity and acceleration of the object at t=1 are 2 and -2 respectively.

(d)

The velocity of the object is 0 at t=2.

Substitute t=2 in the acceleration function to find the acceleration of the object when its velocity is zero.

a=f''(2)=-2

The acceleration of the object is -2 when its velocity is zero.

(e)

The acceleration function of the object is

a=f''(t)=-2

It is a constant function.

Therefore the speed is not increasing at any interval because the acceleration is constant.

7 0
3 years ago
PLEASE PLEASE HELP ME:(( I NEED WORKING AS WELL
mr Goodwill [35]

the equation of the line has form

y=kx+b

\left \{ {{5=k*0+b} \atop {9=k*2+b}} \right. \\b=5\\9=2k+5\\2k=4\\k=2, so

y=2x+5

The second line is parallel to the first and runs 7 units lower, so b=5

0=1k+5\\k=-5\\y=-5x+5

8 0
3 years ago
the area if the triangle is 24 square inches. what is the height if the triangle if the base length is 6 inches​
lara31 [8.8K]

Answer:8

Step-by-step explanation:

The equation for a triangle is base times height times 1/2 so if 8 times 6 gives you 48 once you divide it by two it gives you 24

4 0
3 years ago
Help again pleasepleaseplease
Ilia_Sergeevich [38]

Answer:

9.5

Step-by-step explanation:

The legs of the triangle are

3 and 9

From the Pythagorean Theorem

c² = a²+ b²

c² = 3² + 9²

c² =  = 9 + 81

c² =  90

Take the square root of both sides

c = 9.4868329805

Rounded

9.5

7 0
3 years ago
Find f'(x) for f(x) = 5x2 − 3x + 12. 10x + 12(this answer is incorrect) −10x − 3 10x − 3 None of these
nexus9112 [7]

What are ya sayin

Step-by-step explanation:

5 0
3 years ago
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