3 years ago

PLEASE HELP! I have used the Surface Area of a sphere, but I've just forgot how to solve it

Mathematics

1 answer:

Sever21 [200]3 years ago

3 0

The formula is 4*Pi*R2.

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3 years ago

Please help! 12 points

Ivahew [28]

Answer:

Step-by-step explanation:

sin2x = 2sinx*cosx

= $2\sqrt{sin^{2}x }$ * cosx

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3 years ago

Determine the amplitude or period as requested. Period of a y = - 1/3 * sin x - 1/3 pi/3 1/3 d 2pi

zysi [14]

Answer:

$Period = 2\pi$

Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

Required

Determine the period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = \frac{2\pi}{B}$

By comparing:

$y =A \sin(Bx + C) + D$ and $y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

$Bx = x$

So:

$B = 1$

So, we have:

$Period = \frac{2\pi}{B}$

$Period = \frac{2\pi}{1}$

$Period = 2\pi$

Hence, the period of the function is $2\pi$

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3 years ago

Help me pleaseee thank youu

snow_tiger [21]

Answer:

Step-by-step explanation:

Let's use the formula!

6/-4 - -2/-4 = 8/0.

Since this is divided by 0, this means that it is undefined.

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3 years ago

Margaret manages a second-hand clothing store. The store advertises that is you buy 3 items, you will get 15% off the most expen

denis23 [38]

The answer to this question would be $49.33

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4 years ago

PLEASE HELP! I have used the Surface Area of a sphere, but I've just forgot how to solve it​

PLEASE HELP! I have used the Surface Area of a sphere, but I've just forgot how to solve it