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AleksAgata [21]
3 years ago
14

Can anybody help me with these?​

Mathematics
1 answer:
Masja [62]3 years ago
5 0
A=(-1,-1) B=(1,3)C=(2,5)D=(-2,-3)E=(3,7)
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Solve for x9(x + 1) = 25 + x
vaieri [72.5K]
When you expand the equation, you will have
9x + 9=25 + x
Next you have to collect like terms
+x will go over the equality sign to become -x. The same applies to +9
9x - x=23 - 9
9x minus x is 8x
8x=14
Divide both sides by 8
x=14/8
You will have 1 6/8
6 is the remainder while 1 is the number of times 8 divided 14.
In decimal, it will be 1.75
Hope that helped. Good luck
8 0
3 years ago
Read 2 more answers
For the function Y=5x, what would happen if the value 5 was changed to 3
Daniel [21]

Answer:

y = 3 * x

Step-by-step explanation:

We have the function y = 5 * x, they ask us what would happen if we change the 5 by the 3. thus:

y = 3 * x

the constant that accompanies x in this case is an increase or slope constant, that is, now x will not increase by a ratio of 5, but by a ratio of 3. For example:

If x were worth 10

the value before was 50 and now it will be 30.

I do not increase 5 times but 3 times.

4 0
4 years ago
The table shows the heights of 40 students in a class.
Studentka2010 [4]

Answer:

Step-by-step explanation:

Hello!

a)

The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.

To calculate the mean for data organized in this type of table you have to use the following formula:

X[bar]= (∑x'fi)/n

Where

x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2

fi represents the observed frequency for each class

n is the total of observations, you can calculate it as ∑fi

<u>Class marks:</u>

x₁'= (120+124)/2= 122

x₂'= (124+128)/2= 126

x₃'= (128+132)/2= 130

x₄'= (132+136)/2= 134

x₅'= (136+140)/2= 138

Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.

n= 7 + 8 + 13 + 9 + 3= 40

X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3

The estimated average height is 129.3cm

b)

This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.

The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a  mean value within the interval to calculate the mean of the sample.

I hope this helps!

4 0
4 years ago
I need help fast!
xz_007 [3.2K]

Answer:

D) 180 miles / 6 gallons

Step-by-step explanation:

180 / 6 simplified is 30 / 1. Although C has the same numbers, the numbers are switched. 6 / 180 simplified would be 1 / 30. This is not the same as 30 / 1.

4 0
4 years ago
What is the multiplicative rate of change of the exponential function shown on the graph? 1 4
marta [7]
The answer:
the main formula for computing the multiplicative rate of change is given by:

Mutiplicative Rate of Change = [f(x2)/f(x1)]  / (x2 -x1)
this formula can be written as
 [f(x2)/f(x1)]  / (x2 -x1) = [f(x2) * (x2 -x1) /f(x1)] 

for example we can take (x1, f(x1))= (0, 2) and (x2, f(x2))= (1, 5) 
therefore,
Mutiplicative Rate of Change = [5/2]  / (1-0)= 5/2= 2.5

the answer is 2.5
6 0
3 years ago
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