Answer:
It depends on the structure of the sentence.
Explanation:
This will be shown as grammatical mistake because both the spellings are correct. If we write the word weather instead of the whether, Ms word shows the grammatical mistake. This is because, if we want to write the word whether, we should use or in our sentence. Both of these words are comes together.
Example
I will take a leave whether its raining or not.
In above sentence, both whether and or comes together. If we write weather instead of whether it just show the grammatical mistake in the sentence.
Answer:
a. 227 , b. 74 , c. 249
Explanation:
a. 0x E3 = 227
Hexadecimal Digit E corresponds to decimal number 14.
So decimal representation = 14 * 16 + 3 = 224 + 3 = 227
b. 0x 4A = 74
Hexadecimal Digit A corresponds to decimal number 10.
So decimal representation = 4 * 16 + 10 = 74
c. 0x F9 =
Hexadecimal Digit F corresponds to decimal number 15.
So decimal representation = 15 * 16 + 9 = 240 + 9 = 249
<span>Password procedures, information encryption software, and firewalls are examples of measures taken to address are all measures taken to safeguard information security and protect users data from being tampered or manipulated by invaders.
In web, if we leave our information without encryption or if we leave our system without firewall, different types of security threats might arise: such as, information being hacked, manipulated or sent to wrong places. To avoid this information encryption is done. We might also need to firewall our system so that we can avoid unwanted access and invading of our privacy using malwares and other tools. </span>
Answer:
#include <iostream>
#include <string>
#include <stack>
#include <math.h>
using namespace std;
int main() {
string s;
double n=0;
int position=0;
stack<int> wholeNumbers;
cout<<"Enter a decimal number:";
cin>>s;
string::iterator counter = s.begin();
while(*counter!='.' && counter!=s.end()){
wholeNumbers.push(*counter-48);
counter++;
position=position+1;
}
for(int i=0;i<position;i++){
n=n+(wholeNumbers.top()*pow(10,i));
wholeNumbers.pop();
}
position=-1;
if(counter!=s.end()){
counter++;
}
while(counter!=s.end()){
n=n+((*counter-48)*pow(10,position));
position=position-1;
counter++;
}
cout<<n;
}
Explanation:
- Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
- Increment the counter and position variable by 1 inside the while loop.
- Count the number of digit, push each digit to top of stack and find the end of the number,
- Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
