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Aloiza [94]
3 years ago
8

Find the difference of g(x) and j(x).

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0
To find the answer, subtract j(x) from g(x):

g(x) - j(x)

Plug in the expressions that each function is equal to:

(x^2 - 2x + 11) - (-x^3 - 4x^2 + 5)

Distribute the negative, get rid of parentheses:

x^2 - 2x + 11 + x^3 + 4x^2 - 5

Combine like terms:

x^3 + 5x^2 - 2x + 6
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krok68 [10]
The answer is A.) 17.
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3 years ago
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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
4 years ago
Someone explain I don’t get it
belka [17]

Answer:

neither do I'm stuck on that one

8 0
3 years ago
Enter an equation in point-slope form for the line. Slope is 4 and (−3, −1) is on the line. The equation of the line in point sl
Licemer1 [7]

Answer:

y + 1 = 4 (x + 3)

Step-by-step explanation:

The formula is y - y1 = m (x - x1), so you put the variables in to y1 and x1 plus add the slope in as m, and there you are! Point slope form.

Hope this helps!

3 0
3 years ago
One number exceeds another by 2 the sum of the number is 48 what are the numbers
Bond [772]
x-\ first\ number\\y-\ second\ number\\\\
 \left \{ {{x-y=2} \atop {x+y=48}} \right. \\\\ \left \{ {{x=2+y} \atop {x+y=48}} \right. \\\\Substution\ method\\\\
2+y+y=48\\\\
2+2y=48\\\\
2y=46\ \ \ |:2\\\\
\boxed{y=23}
3 0
3 years ago
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