Find the difference of g(x) and j(x).

1 answer:

6 0

To find the answer, subtract j(x) from g(x):

g(x) - j(x)

Plug in the expressions that each function is equal to:

(x^2 - 2x + 11) - (-x^3 - 4x^2 + 5)

Distribute the negative, get rid of parentheses:

x^2 - 2x + 11 + x^3 + 4x^2 - 5

Combine like terms:

x^3 + 5x^2 - 2x + 6

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Step-by-step explanation:

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three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are

goldenfox [79]

We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure