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Aloiza [94]
3 years ago
8

Find the difference of g(x) and j(x).

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0
To find the answer, subtract j(x) from g(x):

g(x) - j(x)

Plug in the expressions that each function is equal to:

(x^2 - 2x + 11) - (-x^3 - 4x^2 + 5)

Distribute the negative, get rid of parentheses:

x^2 - 2x + 11 + x^3 + 4x^2 - 5

Combine like terms:

x^3 + 5x^2 - 2x + 6
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x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

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What’s 3/4 x 22/7 x 2
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Find inverse of f(x) = 2 + 3x / x - 2
NeX [460]
Okay so, we switch out f(x) with y - I’m sure you know this and we get y=2+3x/x-2.

Now just interchange x and y -> x=2+3y/y-2, now multiply both sides with (y-2), we get (y-2)x=2+3y.

Multiply x with the brackets, getting xy-2x=2+3y. Move 3y to the left changing it’s sign, also for -2x to the right: xy-3y=2+2x.

Factor out y from (xy-3y) and get (3-x)y=2+2x - now divide both sides by (3-x) resulting in y=2+2x/3-x .
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