Find the difference of g(x) and j(x).

1 answer:

6 0

To find the answer, subtract j(x) from g(x):

g(x) - j(x)

Plug in the expressions that each function is equal to:

(x^2 - 2x + 11) - (-x^3 - 4x^2 + 5)

Distribute the negative, get rid of parentheses:

x^2 - 2x + 11 + x^3 + 4x^2 - 5

Combine like terms:

x^3 + 5x^2 - 2x + 6

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lawyer [7]

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3 years ago

A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form

andrey2020 [161]

<span>The general form of quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root
=> x = <u>-b + </u></span><u>√ b^2 – 4 ac</u><span>
2a

It is also written as:
=> ax^2 + bx + c = 0

Quadratic equation involves unknown numbers which is x, the numbers which a, b and c are called coeffecients.
There are also quadratic factorization where you factor the polynomial give to be able to get the value of the equation.</span>

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3 years ago

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Solve the proportional<br> equation below:<br> x/4 = x-6/3

aleksandrvk [35]

<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

$\boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}$