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choli [55]
3 years ago
13

A student took a chemistry exam where the exam scores were mound-shaped with a mean score of 90 and a standard deviation of 64.

She also took a statistics exam where the scores were mound-shaped, the mean score was 70 and the standard deviation was 16. If the student's grades were 102 on the chemistry exam and 77 on the statistics exam, then: a. the student did relatively better on the chemistry exam than on the statistics exam, compared to the other students in each class. b. it is impossible to say which of the student's exam scores indicates the better performance. c. the student did relatively better on the statistics exam than on the chemistry exam, compared to the other students in the two classes. d. the student's scores on both exams are comparable, when accounting for the scores of the other students in the two classes. e. the student did relatively the same on both exams
Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

wow that school has alot of test don't it lol

Step-by-step explanation:

anyway what's the question

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Bill had $5.42 and earned 2.25 he spent $3.78 how much did he have left
inna [77]

Answer:

3.89

Step-by-step explanation:

5.42+2.25=7.67

7.67-3.78=3.89

Hope this helps

8 0
3 years ago
HELP ASAP 10 POINTS TO BRAINLIEST
Brilliant_brown [7]

Answer:

15%

Step-by-step explanation:

The cost of 2 adults and 2 children without the discount is

2 adults = 2 (55) = 110

2 children = 2 (45) = 90

Total cost = 110+90 = 200

The original price is 200 and the new price is 170

Percentage discount = (Original price - new price)/ original price * 100%

                                     = (200-170)/200 * 100%

                                     = 30/200 * 100%

                                     = .15 * 100%

                                     = 15%

6 0
3 years ago
5. Enter the answer as a decimal
Hitman42 [59]

Answer:

6.5%

Step-by-step explanation:

I = prt

5616 = 7200 × r × 12

r = 5616/(7200 × 12)

r = 0.065

r = 6.5%

5 0
2 years ago
HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
2 years ago
Line segment TS is tangent to circle O at point N.
garik1379 [7]

Answer:

  148°

Step-by-step explanation:

The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.

  arc QN = 2(74°) = 148°

_____

<em>Comment on the question and answer</em>

Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.

__

We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.

7 0
4 years ago
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