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Mila [183]
3 years ago
6

In a class of 27 students, five students have 1 pet.

Mathematics
2 answers:
saveliy_v [14]3 years ago
7 0

Answer:

isnt this just 3+4+2+1+12=22. yes there are outliers because 22 doesnt equal 27. there are 5 outliers

Step-by-step explanation:

Digiron [165]3 years ago
3 0

Answer:

yes, the student who has 8 pets.

Step-by-step explanation:

the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"

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1 mile is 6.6 times 800 feet.
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A store is selling lemons at 2 for $3. Each lemon yields 2 tablespoons of lemon juice. How much will it cost to buy enough lemon
igor_vitrenko [27]

Answer:

It will cost $6 to buy enough lemons.

Step-by-step explanation:

Consider the provided information.

To make a 9-inch lemon pie requiring 1/2 cup of lemon juice.

1 cup = 16 tablespoons

1/2 cup = 8 tablespoons

That means we only need 8 tablespoons.

Each lemon yields 2 tablespoons of lemon juice.

Number of lemon required = 8 ÷ 2 = 4

That means we need only 4 lemon.

Store is selling lemons at 2 for $3 that means 4 lemons for $6.

Hence, it will cost $6 to buy enough lemons.

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Salsk061 [2.6K]

Answer:

slope = \frac{4}{5}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

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6 0
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Students attending the University of Florida can select from 130 major areas of study. A student's major is identified in the re
omeli [17]

Answer:

1. 8385 double majors

2. 18252 major codes

3. 8515 codes

4. Yes

Step-by-step explanation:

Given

Major areas = 130

Alphabets = 26

a.

There are 130 major areas in the university.

To get a double majors, means one select any of two of the major areas in the university.

i.e. just 2 alphabets are needed

Number of Double Majors = 130C2

130C2 = 130!/(128!*2!)

130C2 = 130 * 129/2

130C2 = 8385.

b.

Number of major codes available = Number of 2 digit codes + Number of 3 digit codes

Number of 2 digit codes = 2 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

So, number of 2 digit codes = 26 * 26 = 676.

Number of 3 digit codes = 3 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

There are 26 ways of selecting the third letter

So, number of 3 digit codes = 26 * 26 * 26 = 17576

Thus, number of major codes = 17576 + 676 = 18252

c.

Number of codes to identify a student with either a single major or double major

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Number of double major codes = 8385

Total = 130 + 8385 = 8515

d. From the solutions above, Yes there are enough codes available to identify all single and double majors at the university

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3 years ago
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