All categories

3 years ago

In a class of 27 students, five students have 1 pet.

Mathematics

2 answers:

saveliy_v [14]3 years ago

7 0

Answer:

isnt this just 3+4+2+1+12=22. yes there are outliers because 22 doesnt equal 27. there are 5 outliers

Step-by-step explanation:

Digiron [165]3 years ago

3 0

Answer:

yes, the student who has 8 pets.

Step-by-step explanation:

the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"

You might be interested in

Will give brainliest if correct Pls help thanks :)

lidiya [134]

Domain:
{-1, 3, 6}

Range:
{4, 5, 6}

6 0

3 years ago

If you could help I would really appreciate it, but if not that’s fine. Thank you.

zloy xaker [14]

Answer:

2x - 5 if x ≤ 2

f(-1) = -7

Step-by-step explanation:

x ≤ 2 = (-1) ≤ 2

x > 2 = (-1) > 2

2x - 5

2(-1) - 5

-2 - 5

-7

8 0

2 years ago

Completely Factor 2n^2-23n+45=0

Anton [14]

Answer:

x=5/2, 9

Step-by-step explanation:

3 0

3 years ago

Please help ! solve for x A) 27 B) 2 C) 8 D) 12

diamong [38]

Answer:

I think its 2 but Idk how to show work sorry

Step-by-step explanation:

3 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes