Which of the following will increase the gravitational force exerted by one object on another? No links plz

Ms. Good has a bag of 15 marbles. Three are blue, six are red, and six are yellow. What is the probability that she picks a yell

Delicious77 [7]

Answer:

the chances of her picking a yellow one is 6 in 15

Step-by-step explanation:

all you have to do is divide the color that you are trying to find the probability of by the amount of that object is if that makes sense.

5 0

2 years ago

Read 2 more answers

Help is needed please!

Schach [20]

The distance travelled is 10 m

The velocity gained at the end of the time is 2 m/s

<h3>Motion</h3>

From the question, we are to determine distance travelled and the velocity gained

From one of the equations of motion for <u>linear motion</u>, we have that

S = ut + 1/2at²

Where S is the distance

u is the initial velocity

t is the time taken

and a is the acceleration

First, we will calculate the acceleration

Using the formula,

F = ma

Where F is the force

m is the mass

and a is the acceleration

∴ a = F/m

Where F is the force

and a is the acceleration

From the given information,

F = 50 N

m = 250 kg

Putting the parameters into the equation,

a = 50/250

a = 0.2 m/s²

Thus,

From the information,

u = 0 m/s (Since the object was initially at rest)

t = 10 s

S = 0(t) + 1/2(0.2)(10)²

S = 10 m

Hence, the distance travelled is 10 m

For the velocity

Using the formula,

v = u + at

Where v is the velocity

v = 0 + 0.2×10

v = 2 m/s

Hence, the velocity gained at the end of the time is 2 m/s

Learn more on Motion here: brainly.com/question/10962624

#SPJ1

7 0

1 year ago

Guys Help!! I Don´t Know How To Do This!!

Shkiper50 [21]

Answer:

Frank

Step-by-step explanation:

First let's start by calculating the speed of each runner.

Let's use feet per second

Frank's speed is already given in feet per second: 14 feet/second

We are given that Jake runs 382 feet in 38 seconds. To bring this down to feet/second we need to divide both numbers by 38.

382/38=10.05 feet/second (about)

We are given that Will runs 1 mile in 394 seconds. 1 mile is equivalent to 5280 feet. Now we divide both numbers by 394 to bring it down to feet/second.

5280/394=13.401 feet/second (about)

We are given that Ron runs 555 feet in 1 minute. 1 minute is equivalent to 60 seconds. Now we divide both numbers by 60 to bring it down to feet/second.

555/60=9.25 feet/second

After comparing all the speeds, we can conclude that Frank runs the fastest

5 0

2 years ago

Round 27.2847 to the nearest a. tenth and b. hundredth. SHOW YOUR WORK AND NO LINKS PLEASE, THANK YOU!

Finger [1]

Answer:

A. 27.3

B. 27.28

Step-by-step explanation:

You would have to round the tenth place up because of the 8 in the hundredths place, and for the hundredth place you would have to see if the thousandths place is higher than a 5 and if not don’t round up.

7 0

2 years ago

Read 2 more answers

A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere

timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

( x - 300 ) , and the price decrease

(1/80)*40 = 0,5

Then the demand function is:

D(x) = 600 - 0,5* ( x - 300 ) (1)

And revenue function is:

R(x) = x * (D(x) ⇒ R(x) = x* [ 600 - 0,5* ( x - 300 )]

R(x) = 600*x - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) = 450 - x

R´(x) = 0 ⇒ 450 - x = 0

x = 450 units

We can observe that for 0 < x < 450 R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450) = 600 - 0,5* ( x - 300 )

D(450) = 600 - 225 + 150

D(450) =

D(450) = 600 - 0,5*( 150)

D(450) = 600 - 75

D(450) = 525

And the rebate must be

600 - 525 = 75 $

5 0

3 years ago