Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Y=1/3x+2
(-6,0)
(0,2)
(6,4)
2.64 divided by 6 equals 0.44. one ounce costs 44 cents
12z^2 - 7z -12/ 3z^2 + 2z - 8
= (4z+3) (3z -4)/ (z+2)(3z -4)
= (4z + 3) / (x+2)
Hope this helps
Answer:
9;10
Step-by-step explanation:
What we can first do is make them into one double sided inequality and then interpret it from there.
After combining them we get: 7<x<12
This means that any number between 7 and 12 can be picked.
Keep in mind, this means that 7 and 12 cannot be picked, they have to be in between.
Therefore, we get our aswers of 9 and 10!
