A: the outlier would be 7500 because it is not as close to the other prices
Answer:
(-2, -3)
Step-by-step explanation:
We assume your system of equations is ...
You can subtract the second equation from the first to get
... (2x -y) -(2x -4y) = (-1) -(8)
... 3y = -9 . . . . . collect terms
... y = -3 . . . . . . divide by 3 . . . . this is sufficient to identify the correct answer
Substituting into the first equation, we have ...
... 2x -(-3) = -1
... 2x = -4 . . . . . add -3
... x = -2 . . . . . . .divide by 2
Now, we're sure the answer is (x, y) = (-2, -3).
Answer:
A-1
Step-by-step explanation:
It perfectly represents the scenario.
20
This is because
2x+(6x+20)=180
8x+20=180
8x=160
8x/8=160/8
X=20
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
