The linear equation that defines the line G can be written as:
y = -(1/3)*x + 5
<h3>How to get the equation of the line G?</h3>
A general linear equation written in the slope-intercept form is:
y = a*x + b
Where a and b are real numbers, a is the slope and b is the y-intercept.
If we know that the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is:
a = (y₂ - y₁)/(x₂ - x₁)
In this case we know that the line passes through (-3, 6) and (0, 5), then the slope is:
a = (5 - 6)/(0 - (-3)) = -1/3
The linear equation is something like:
y = (-1/3)*x + b
We know that it passes through (0, 5), then:
5 = (-1/3)*0 + b
5 = b
We conclude that the linear equation can be written as:
y = -(1/3)*x + 5
If you want to learn more about linear equations:
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Answer:
Step-by-step explanation:
Given that two digit numbers are used and one digit is drawn randomly.
Sample space = {10,11,...99}
n(S) = 90
32 is only one number favourable
Hence P(32) = 1/90
----------------------------
Odd numbers are exactly 45.
Hence prob (odd number) = 45/90 = 1/2
-------------------------------------
Multiples of 5 are 10,15,.....95
There are exactly 18 numbers.
Hence P(a multiple of 5) = 18/90 =1/5
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For this case we have an equation of the form:
Where,
v0: initial value in assets
b: depreciation rate
t: time in years.
Substituting values we have:
For year 8 we have:
Rounding off we have:
V (t) = 83401
Answer:
the value of V0 and b are:
V0 = $ 408,000
b = 0.82
the value of the assets after 8 years is:V (t) = 83401 $
X-8=3x+6
(Minus 3x and add 8 to group your variables)
-3x+x=8+6
-2x=14
-2x/-2 = 14/-2
X=-7
