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3 years ago

In its SIMPLIEST form, what is the Entscheidung problem? (Definition for dummies

1 answer:

8 0

A challenge posed by David Ackerman in 1928 The problem is an algorithm that considers, an input, a statement and answers (like yes and no) according to whether the statement is universally valid in every structure satisfying the axioms

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someone please help, write in point-slope form an equation of the line that passes through the point (8, 9) with slope 7.

Bess [88]

Answer:

y=7x-47

Step-by-step explanation:

$(8, 9) = (x_1,y_1) \\ m = 7 \\ y - y_1 = m(x - x _1) \\ y - 9 = 7(x - 8)$

$y - 9 = 7x - 56 \\ y = 7x - 56 + 9 \\ y = 7x - 47$

7 0

3 years ago

Which ratio is equivalent to 4.5? 10 15 4 10 16 20 15 8

bekas [8.4K]

Answer:

8:10 and 12:15

Step-by-step explanation:

to find the two equivalent ratios of 4:5 we need to apply multiplication method only to get the answer in integer form therefore, the equivalent ratios of 4:5 are 8:10 and 12:15

6 0

3 years ago

Read 2 more answers

Please help me with this question please

Arturiano [62]

Answer is the last choice

2a-4/1= -a-1/a-4
Cross multiply
(2a-4)(a-4)= -(a-1)
2a^2-8a-4a+16= -a+1
Bring right to left sign change signs
2a^2-8a-4a+16+a-1=0
Combine like terms
2a^2-11a+15=0

a= 2 b= -11 c= 15
Use quadratic formula

-b+-sq rt of b^2-4ac. Divided by 2a

-(-11) +- 11^2-4(2)(15) divided by 2(2)
11+-sq rt 121-120 divided by 4

11+1 /4. 11-1/4
12/4. 10/4
3. , 5/2

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3 years ago

Find the remainder when f(x) is divided by x - k. 9) f(x) = x' - 8x? - 10x² – 24x

OlgaM077 [116]

Answer: Graphing a Quadratic Function

y=−10x2−31x

Step-by-step explanation:

Graphing a Quadratic Function

f(x) ÷ x - k.

9) f(x) = x' - 8x? - 10x² – 24x

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4 years ago

Mia found the area of a polygon The area is 32 square cm.

solniwko [45]

Answer:

Only the isosceles trapezoid has an area of 32 cm².

Step-by-step explanation:

Let's calculate the area of each polygon.

For the two triangles we have:

$A_{t} = \frac{bh}{2} = \frac{2 cm*4 cm}{2} = 4 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle we have:

$A_{r} = bh = 6 cm*4 cm = 24 cm^{2}$

This polygon does not have an area of 32 cm².

For the rectangle trapezoid we have:

$A_{rt} = A_{t} + A_{r} = (4 + 24) cm^{2} = 28 cm^{2}$

So, this polygon does not have an area of 32 cm².

Finally, for the isosceles trapezoid:

$A_{it} = A_{t}*2 + A_{r} = (4*2 + 24) cm^{2} = 32 cm^{2}$

This polygon does have an area of 32 cm².

Therefore, only the isosceles trapezoid has an area of 32 cm².

I hope it helps you!

8 0

3 years ago