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Anvisha [2.4K]
3 years ago
10

Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 3 units long.Point C is on the line x = -1.

If the area of AABC is 6 square units,
then find a possible y-coordinate of point
05
06
07
08

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

6

Step-by-step explanation:

Area = 1/2( base times height)

since the height is perpendicular to the base

therefore

6 = 1/2(3) h

12 =3h

4=h

4 units away from the y=2 line is at the y coordinate of 6

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What is the solution to y = 2x + 3 for the replacement set x = {1.3}?
storchak [24]
The solution is


y=5.6


hope this helps:)
5 0
3 years ago
I'll add a photo of the problem! ​
eduard

Answer: D

Step-by-step explanation:

7 0
3 years ago
Please help!! No like or I will report!​
Marina86 [1]

Answer:

B . 3600π m²

is the answer

Step-by-step explanation:

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6 0
3 years ago
(can someone please help me answer this question i will make you brainliast)
cricket20 [7]

Answer:

x = 5\sqrt{3}

Step-by-step explanation:

Using the tangent ratio and the exact value

tan60° = \sqrt{3} , then

tan60° = \frac{opposite}{adjacent} = \frac{x}{5} = \sqrt{3} ( multiply both sides by 5 to clear the fraction )

x = 5\sqrt{3}

5 0
3 years ago
Help me please please please
morpeh [17]

Answer:

Step-by-step explanation:

let coordinates of D are (x,y)

mid point of AC=midpoint of BD

so{ (-3+4)/2,(1+6)/2}={(x+(-1))/2,(y+4)/2}

(1/2,7/2)={(x-1)/2,(y+4)/2}

(x-1)/2=1/2

x-1=1

x=1+1=2

(y+4)/2=7/2

y+4=7

y=7-4=3

so D is (2,3)

4 0
3 years ago
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