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3 years ago

A car travels 120 miles in 3 hours

Mathematics

2 answers:

Kipish [7]3 years ago

5 0

Answer:

120 miles = 3 hrs

1 mile = 3/120 = 1/40

200 miles = 1/40 × 200

= 5 hrs

Step-by-step explanation:

Rainbow [258]3 years ago

4 0

1) the car travels at 40 mph (I think you meant fast instead of far)
2) the car would travel 320 miles

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Black_prince [1.1K]

It might be 0.36 or 0.66. Sorry if that doesn’t help

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3 years ago

NEED HELP !!!!! Pasbmsbsjshdvssndbns

Firlakuza [10]

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3 years ago

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natka813 [3]

The value of x from the given circle is 12

<h3>Circle theorem</h3>

Angle at the vertex of the circle is half the angle at its intercepted arc.

From the given circle;

The measure of <DEF = 80/2 = 4x -8

Equate both angles

4x - 8 = 80/2

Add 8 to both sides

4x - 8 + 8 = 40 + 8

4x = 48

x =12

Hence the value of x from the given circle is 12

Learn more on circle theorem here: brainly.com/question/26594685

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2 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD = 12

Dmitry [639]

Answer:

x = 6

Step-by-step explanation:

let 'x' = BD

x/3 = 12/x

x² = 36

x = $\sqrt{36}$

x = 6

5 0

3 years ago

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago