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2 years ago

12

Put down ur best memes here! And help me.. whats 0+0

2 answers:

solong [7]2 years ago

4 0

Answer:

lol i dont have a meme sorry but 0+0 is 0 haha

Step-by-step explanation:

thx!

forsale [732]2 years ago

3 0

Answer:

lol

Step-by-step explanation:

hey timmy

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AleksAgata [21]

Answer:

Step-by-step explanation:

4 0

2 years ago

If B = { p : p is a factor of 12 } list the elements of this set and find n ( B )

anastassius [24]

Answer:

B={1,2,3,4,6and12}

n (B) =6

Step-by-step explanation:

<h3>Greetings !</h3>

Factor, in mathematics, a number or algebraic expression that divides another number or expression evenly—i.e., with no remainder. For example, 3 and 6 are factors of 12 because 12 ÷ 3 = 4 exactly and 12 ÷ 6 = 2 exactly. The other factors of 12 are 1, 2, 4, and 12.

Hope it helps!

3 0

1 year ago

Is the relation a function? Why or why not?

uranmaximum [27]

Answer: A; No, the relation passes the vertical line test.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The points (-1.6, 2.7) and (3.2, 7.98) are on the graph of a linear relationship between two variables, r and y.

Aleksandr [31]

Answer:

y = 1.1x +4.46

y = 129.86 for x = 114

Step-by-step explanation:

The two-point form of the the equation for a line is useful for this.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (7.98 -2.7)/(3.2 -(-1.6))(x -(-1.6)) + 2.7

y = 5.28/4.8(x +1.6) + 2.7

y = 1.1x +1.76 +2.7

y = 1.1x +4.46

__

When x=114, the value of y is ...

y = 1.1(114) +4.46

y = 129.86

6 0

2 years ago

What is the equation of the line perpendicular to Y-3x+1 that passes through the point (12,-6)?

erma4kov [3.2K]

Answer:

$3y + x = -6$

Step-by-step explanation:

Given

y = 3x + 1

Required

Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1

First, the slope of the line has to be calculated;

Th slope of a line is the coefficient of x in its linear equation;

This implies that the slope of y = 3x + 1 is 3

Having calculated the slope of the first line;

The relationship between both lines are perpendicularity; this implies that $m_1 * m_2 = -1$

Where m_1 = 3 and m_2 is the slope of the secodnd line

$m_1 * m_2 = -1$ becomes

$3 * m_2 = -1$

Divide both sides by 3

$\frac{3 *m_2}{m_2} = \frac{-1}{3}$

$m_2 = \frac{-1}{3}$

The equation of the line can be calculated using the folloing formula

$m = \frac{y - y_1}{x - x_1}$

Where $(x_1, y_1) = (12,-6)$ and $m_2 = \frac{-1}{3}$

The equation becomes

$\frac{-1}{3} = \frac{y -- 6}{x - 12}$

$\frac{-1}{3} = \frac{y + 6}{x - 12}$

Cross multiply

$-(x - 12)= 3(y + 6)$

$-x + 12=3y + 18$

Collect like terms

$12 - 18 = 3y +x$

$-6 = 3y + x$

$3y + x = -6$

4 0

2 years ago