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2 years ago

Put down ur best memes here! And help me.. whats 0+0

Mathematics

2 answers:

solong [7]2 years ago

4 0

Answer:

lol i dont have a meme sorry but 0+0 is 0 haha

Step-by-step explanation:

thx!

forsale [732]2 years ago

3 0

Answer:

lol

Step-by-step explanation:

hey timmy

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How many solutions exist for the system below? In two or more complete sentences, give the solution and explain how you solved t

11Alexandr11 [23.1K]

Answer:

See below

Step-by-step explanation:

y=-2x + 3

y = -2*3x

Both equations are lines.

Two lines will intersect at one point

I will set the two equations equal and solve for the x coordinate.

-2x+3 = -6x

Add 2x from each side

3 = -4x

Divide by -4

-3/4 = x

Now find y

y = -6x

y = -6(-3/4)

y = 18/4 = 9/2

The solution is ( -3/4, 9/2)

7 0

2 years ago

Find the sum. 185 + 66

dusya [7]

So all you need to do in order to find the sum is add so 185+66=251

3 0

2 years ago

Read 2 more answers

The first triangle is an enlargement of the second.

insens350 [35]

Answer:

large triangle:

base = 6.64 cm

hypotenuse = 8.31 cm

small triangle:

base = 4 cm

Step-by-step explanation:

large triangle:

tan 37 = 5/base

0.7536 = 5/base

base = 6.64 cm

using the Pythagorean theorem:

hypotenuse² = 5² + 6.64²

hypotenuse² = 25 = 44.02 = 69.02

hypotenuse = 8.31 cm

small triangle:

using the Pythagorean theorem:

base² = 5² - 3²

base² = 25 - 9 = 16

base = 4 cm

3 0

2 years ago

Hiiiiiiiiiiiiiiiiii Need helpppppppppppp

kirill115 [55]

Answer:

Step-by-step explanation:

Angles around a point add up to 360

x + 53 + 37 + 139 = 360

x + 229 = 360

x = 360 - 229

x = 131

7 0

2 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

1 year ago

Read 2 more answers